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3 years ago

Help please! I dont understtand

Mathematics

2 answers:

balandron [24]3 years ago

7 0

it is skewed left bud

Nataliya [291]3 years ago

4 0

Skewed left

for sure because the its not dipping back down, bell shape, at the end, one side isnt the same number, repeating , and it doesnt get smaller as the other gets bigger.

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Write an equation of the line that passes through (3,1) and (0,10)

tangare [24]

Step-by-step explanation:

use the slope formula

y2-y1 / x2-x1

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2 years ago

List the values that make up the domain of this relation.

balandron [24]

$\bf (\stackrel{\downarrow }{5},3),(\stackrel{\downarrow }{2},-7),(\stackrel{\downarrow }{1},-8),(\stackrel{\downarrow }{8},3)\qquad \quad \stackrel{\textit{the domain is always the set of the 1st coordinate}}{(5,2,1,8)}$

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3 years ago

What is the total area of a cylinder that has a radius of 5 cm and a height of 12 cm

Grace [21]

376.99 try that the formula is 2x3.14x5x12

5 0

3 years ago

Whats is the diference of:

grandymaker [24]

Answer:

$2h^2$

Step-by-step explanation:

=> $(10h^4+h^2)-(10h^4-h^2)$

=> $10h^4+h^2-10h^4+h^2$

=> $h^2+h^2$

=> $2h^2$

7 0

3 years ago

Find the area of the shape below.

m_a_m_a [10]

Answer:

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not give the dimensions of the triangle and the dimensions of the square, I will giveyou a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

$A_{triangle}=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

And the area of a square can be found with this formula:

$A_{square}=s^2$

Where "s" is the length of any side of the square.

Therefore, the area of the shape will be

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

3 0

3 years ago