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IgorLugansk [536]
3 years ago
11

I’m being timed help!!!!!!!!!!!!!!

Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer:

3x - y = -2

Step-by-step explanation:

Evgen [1.6K]3 years ago
7 0

Answer: light blue

Step-by-step explanation: Ax + By = C

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For the equation, 1/2x - 3 + 4, what would be the y-intercept?
ryzh [129]

Answer:

1

Step-by-step explanation:

the y-intercept is -1 since 4-3 is 1

3 0
3 years ago
Read 2 more answers
Write a rule for the function:<br><br> 1 6<br> 2 11<br> 3 16<br> 4 21
PolarNik [594]

Answer:

4 21

Step-by-step explanation:

Its probably the answer you are looking for

8 0
1 year ago
What is 10 times 2.50?
dolphi86 [110]
Twenty five dollars answeris

4 0
3 years ago
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For her parents' anniversary party, Ellie is considering using one of two venues. A hotel in
kompoz [17]

The hotel is $250 plus $25 per person so the equation would be

y= 25x + 250

(Y is the total cost and x is the number of people)

the restaurant is $100 plus $40 per person so the equation would be

y = 40x + 100

What we want to know is which x value would make the y values equal to each other. So you can just replace the "y" in one equation with the other equation:

25x + 250 = 40x + 100

and then solve...

1. subtract 100 from both sides

    25x + 150 = 40x

2. subtract 25x from both sides

    150 = 15 x

3. divide both sides by 15

    10 = x

you can check by plugging 10 into the original equations

25(10) + 250

250 + 250 = 500

and

40(10) + 100

400 + 100 = 500

they both cost $500 when you invite 10 people

6 0
3 years ago
Factor x2+12x+35 , I appreciate all the kind generous help I can receive
stellarik [79]
So, to factor out the equation x²+12x+35, first multiply the first and last numbers.
1×35=35
So, you need to find the multiples of 35 that add up to 12.
So, you find 7 and 5. These two numbers are the magic numbers that will be used as the correct factored form of x²+12x+35, because:
>7×5=35
>7+5=12
So, using these two numbers, you get your factored form as:
(x+5)(x+7)
8 0
3 years ago
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