Answer:
A. 45°
Step-by-step explanation:
The smallest interior angle measure of any regular polygon is that of an equilateral triangle: 60°.
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The corresponding exterior angle measure for interior angle x will be its supplement: 180° -x. This value must be a divisor of 360° 360° is not evenly divisible by 180°-45°=135°.
Answer:
28 non-blue marbles.
Step-by-step explanation:
Initial probability of choosing a blue marble = 4/12
Let the number of non-blue marbles to be added be x.

(cross multiply)

Answer:

Step-by-step explanation:
Let's re-write the equations in order to get the variables as separated in independent terms as possible \:
First equation:

Second equation:

Third equation:

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

Now we use this value for "x" back in equation 1 to solve for "y":

And finally we solve for the third unknown "z":

Answer:
h=
Step-by-step explanation:
1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is
.....So it would look like:

2.) Simplify the equation if you need to (in this case, its not needed)

That's your answer :)
Assuming what is meant by "infinite solutions" are infinite number of solutions of a logarithmic equation.

and
