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zmey [24]
3 years ago
10

Two separate linear functions are expressed by the graph and by the equation. Select all that apply.

Mathematics
2 answers:
Andre45 [30]3 years ago
4 0

Answer:

First option: The slope is negative for both functions.

Fourth option: The graph and the equation expressed are equivalent functions.

Step-by-step explanation:

<h3> The missing graph is attached.</h3><h3> </h3>

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Given the equation:

y=-4x-4

We can identify that:

m=-4\\b=-4

Notice that the slope is negative.

 We can observe in the graph that y-intercept of the other linear function is:

b=-4

Then, we can substitute this y-intercept and the coordinates of a point on that line, into y=mx+b and solve for "m".

Choosing the point (-2,4), we get:

4=m(-2)-4\\\\4+4=-2m\\\\m=-4

Notice that the slope is negative.

Therefore, since the lines have the same slope and the same y-intercept, we can conclude that they are equivalent.

MakcuM [25]3 years ago
3 0

Answer:

correct answer: the slope is negative for both functions and the slope of the line in the graph is -2.

Step-by-step explanation:

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Acute

Step-by-step explanation:

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3 years ago
Can you identify a parallel or perpendicular equation and type the correct code?
AlladinOne [14]

Answer:

The equation of the line that is parallel to  is  and the equation of the line that is perpendicular to  is .

Let be a line whose equation is:

(1)

Whose explicit form is:

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Where:

- Independent variable.

- Dependent variable.

The slope and x-intercept of the line are  and , respectively.

There are two facts:

A line is parallel to other line when the former has the same slope of the latter.

A line is perpendicular to other line when the former has a slope described the following form (), where  is the slope of the former.

Then, the equation of the line that is parallel to  is  and the equation of the line that is perpendicular to  is .

To learn more on lines, we kindly invite to check this verified question: brainly.com/question/2696693

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3 0
2 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
The result of a subtraction problem is called a quotient
Shalnov [3]
The answer to a divisionproblem
3 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
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