3 years ago

I have no idea about this

Mathematics

1 answer:

Artist 52 [7]3 years ago

7 0

3: 8 4: 11 6: 15 7: 17 8: 9 10: 7 11: 13 12: 9

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can someone please help me with this? i know it’s change of base formula i just don’t know how to work it out

ANTONII [103]

I still cant see it sorry cant help without seeing it can you spell the question?

3 0

3 years ago

307,407 rouned to the nereist thousandth

kobusy [5.1K]

Rounded to the thousands would be 307,000 and thousandths is 307.407

6 0

3 years ago

Find the equation of a line that passes through the point (3,1) and has a gradient of -3. Leave your answer in the form y = m x

Bingel [31]

Answer:

$y = (-3)\, x + 10$ .

Step-by-step explanation:

The question requires that the equation should be in the slope-intercept form $y = m \, x + c$ . The $m$ and $c$ in this equation are constants. In particular:

$m\!$ would represent the slope of this line (also known as the gradient of this line,) whereas
$c$ would be the $y$ -intercept of this line.

The question states that the slope of this line is $(-3)$ . Therefore, $m = -3$ . Thus, the equation for this line should be in the form $y = (-3)\, x + c$ .

The value of constant $c$ could be found using the other piece of information: the point $(3,\, 1)$ is in this line. In other words, the solution $\text{$x = 3$ and $y = 1$}$ should satisfy the equation $y = (-3)\, x + c$ .