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Len [333]
3 years ago
13

A = {3, 5, 7, 9} and B = {1, 2, 4, 6, 7, 9}

Mathematics
1 answer:
never [62]3 years ago
5 0

Answer:

A∩B={7,9}

Option A is correct option.

Step-by-step explanation:

We are given:

A = {3, 5, 7, 9} and B = {1, 2, 4, 6, 7, 9}

and we need to find A intersects with B i.e. A∩B

We find A intersects with B, we will consider only those terms that are common in both A and B

So,

A∩B= {3, 5, 7, 9} ∩ {1, 2, 4, 6, 7, 9}

As 7 and 9 are only common in both A an B

A∩B={7,9}

So, we get: A∩B={7,9}

Option A is correct option.

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algol13

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b) Both 1,004 and 251 are greater than 10.

Step-by-step explanation:

p = 0.80

n = 1255

In order to use CLT the distribution of \hat{p} should have np and n(1-p) greater than 10.

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4 0
4 years ago
OBC is a sector of a circle with centre o and radius 9cm work out the area of the shaded region as a percentage of the area of s
NARA [144]

Answer:

83.7 %

Step-by-step explanation:

To get the area of the shaded region, we will following these steps.

Step one: Get the area of the sector of the circle.

The area of the sector of the circle can be obtained using the formula:

Area = \frac{\theta}{360}\times \pi r^{2}

Theta will be 60 degrees because triangle OAD is an equilateral triangle

Hence, Area = \frac{60}{360}\times \pi \times 9^{2}= 42.42cm^{2}

Step Two: Get the area of the equilateral triangle

The area of the equilateral triangle can be got using the formula

Area = \frac{1}{2} Base \times Height

The height of the triangle can be got by drawing an imaginary line bisecting the triangle into two parts and applying the Pythagoras' theorem to any of the resulting right-angled triangles formed.

This will be height =\sqrt{4^{2}-2^{2}} =3.46cm

Thus Area = \frac{1}{2}\times 4\times 3.46=6.93cm^{2}

Step Three: Subtract the area of the triangle from the area of the sector

Area of the shaded portion = 42.42cm^{2}-6.93cm^{2}=35.49cm^{2}

Step Four: Divide the area of the shaded portion by the area of the entire shape and multiply the result by 100:

Expressing the ratio of the two areas as a percentage, we have

\frac{35.49}{42.42} \times 100\approx 83.7 % %

7 0
3 years ago
684658 rounded to the nearest one thousand
umka21 [38]
685000  that is the answer

5 0
3 years ago
Read 2 more answers
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