Answer:
A
Step-by-step explanation:
22-10=12
total cost=5+12×0.50
=5+6
=11 $
We have 2 types of tickets, A tickets and B tickets. The total number of tickets sold was 500, so an equation for this NUMBER of tickets is A + B = 500. The MONEY equation is something different. A tickets cost 10, so they are represented by 10A; B tickets cost 60, so they are represented by 60B. The total dollar sales for A and B are 6000. Our money equation for the sales is 10A + 60B = 6000. Solve the first equation for A: A = 500 - B. Sub that value for A into the second equation to solve for B: 10(500-B) + 60B = 6000. Distribute through the parenthesis to get 5000 - 10B + 60B = 6000. Combine like terms to get 50B = 1000. B = 20. There were 20 type B tickets sold. A = 500 - B, so A = 500 - 20 and A = 480. There were 480 type A tickets sold.
Answer:
- 20 - (3 × 23 - 5) =
- 20 - (69 - 5) =
- 20 - 64 =
- - 44
Note.
<em>The answer options are not matching the question. Something is wrong with the question.</em>
Answer:
a = 7
Step-by-step explanation:
The function given is defined at x=1 as ...
f(1) = 3·1² = 3
In order to make the limit from the left be 3, we must have ...
ax -4 = 3 . . . . for x=1
1a = 7 . . . . . . .add 4
The value of the constant "a" is 7.