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Alexandra [31]
4 years ago
8

A toy store ordered 26 crates of stuffed bears.

Mathematics
2 answers:
lbvjy [14]4 years ago
8 0
C. 500
Because you do 26 times 21 and it equals 546 and it is closer to 500 than 900
Hope it helps
9966 [12]4 years ago
4 0

Answer: C500

Step-by-step explanation: you would multiply 26 and 21 = 546 the round that out and you get C

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Does the choice of the base affect the perimeter of a triangle?
forsale [732]
No. 
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The sum of three numbers doesn't depend on what order you
add them ... I think that's the 'commutative' property of addition. 

So it doesn't matter which side you start with, or even what order
the sides are arranged in.  The perimeter is always the same.
7 0
3 years ago
Which of these is the algebraic expression for "4 times the sum of 2 and y?"
solmaris [256]

Answer:

b

Step-by-step explanation:

The sum of 2 and y is 2 + y, then 4 times this sum is

4(2 + y) → b

4 0
3 years ago
Write an expression to represent:<br> One less than the quotient of four and a number x.
sveticcg [70]

Answer:

4/x-1 is the correct answer

Step-by-step explanation:


3 0
4 years ago
In a lottery game a player wins $1,000,000 with probability 0.0000005, wins $200,000 with probability0.000002, and wins $30,000
MariettaO [177]

Answer:

X_1 = 1000000 , P(X_1)= 0.0000005

X_2 = 200000 , P(X_2)= 0.000002

X_3 = 30000 , P(X_3)= 0.00001

X_4 = -2, P(X_4) = 1-0.0000005-0.000002-0.00001= 0.9999875

And then replacing we have this for the expected value:

E(X) = 1000000*0.0000005 +200000*0.000002+30000*0.00001 2*0.9999875

And after do the math we got:

E(X) = -0.79998

And then the expected value for this game is -0.79998 a negative result means NOT a win.

Step-by-step explanation:

For this case we can define the random variable X as the amount that we can win. We can find the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And we have the following probabilities and possible values given:

X_1 = 1000000 , P(X_1)= 0.0000005

X_2 = 200000 , P(X_2)= 0.000002

X_3 = 30000 , P(X_3)= 0.00001

X_4 = -2, P(X_4) = 1-0.0000005-0.000002-0.00001= 0.9999875

And then replacing we have this for the expected value:

E(X) = 1000000*0.0000005 +200000*0.000002+30000*0.00001 2*0.9999875

And after do the math we got:

E(X) = -0.79998

And then the expected value for this game is -0.79998 a negative result means NOT a win.

7 0
3 years ago
Did I do this right?
Dimas [21]
Yeah that’s correct
5 0
3 years ago
Read 2 more answers
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