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Marrrta [24]
3 years ago
14

I need help ASAP PLEASEEEEEEEEEEEEEEEEEE

Mathematics
2 answers:
pashok25 [27]3 years ago
6 0

Answer:


Step-by-step explanation:

Here is another method. It might be shorter. You can decide. Make sure that the numbers are odd by doing this

2k + 1  is one of the odd numbers. 2k is even. When you add 1 to 2k + 1 is odd.

2k - 1 is another member of this family

2k + 3 is a third member

2k - 3 is the fourth member.

When you add them, all the coefficients will cancel out.

2k + 1 + 2k - 1 + 2k - 3 + 2k + 3 = 400   Add

8k = 400                                                 Divide by 8

k = 400/8

k = 50

2k + 1 = 2*50 + 1 = 100 + 1 = 101

2k - 1 =  2*50 - 1 = 100 - 1 = 99

2k + 3 = 2*50 + 3 = 103

2k - 3 = 2*50 - 3 = 97

You don't really need to use 2k. You can do the same thing with n - 1 and n + 1 and n - 3 and n + 3. The same thing will happen: all the coefficients will cancel.


Oksanka [162]3 years ago
5 0

Answer:

97,99,101,103

Step-by-step explanation:

Let x = first odd integer

x+2 = 2nd odd integer

x+4 = 3rd odd integer

x+6 = 4th odd integer

Sum of 4 odd integers is 400

x+ (x+2) + (x+4)+(x+6) = 400

Combine like terms

4x +12 = 400

Subtract 12 from each side

4x+12-12 = 400-12

4x = 388

Divide by 4 on each side

4x/4 = 388/4

x=97

The first integer is 97

The 2nd is 97+2 =99

The third ix 97+4 = 101

The 4th is 97+6 = 103

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the graph below plots a function f x if x represents time the average rate of change of the function f x in the first three seco
Vinvika [58]

Answer:

-50

Step-by-step explanation:

rate of change = slope so you were asked for the slope between the point in which x = 0 (0,150) and the point in which x=3 (3,0)

Here is how you calculate it:

https://simplisico.com/share/q/ZAHw5oFz9yYoOV0BmMRwQI9U

4 0
3 years ago
PLS HELP ME ANSWER THIS OR I CANT DO GYM TODAY
Alekssandra [29.7K]

<u>On the first part, just replace the variables with the given number to check. </u>

1) 34 + 12 = 46 → <u>Correct</u>

2) 22 - 9 = 14 → <u>Incorrect</u>  

3) 6 * 9 = 54 → <u>Correct</u>

4) 39 ^ 3 = 13 → <u>Correct</u>

<u />

<u>On the second part, simply change the symbols. Like this:</u>

5) 7 + k = 11 ⇒ 11 - 9 = k  

     <u>K = 2 </u>

6) p - 24 = 13 ⇒ 13 + 24 = p

  <u> p = 37 </u>

7) b - 16 = 7 ⇒ 7 + 16 = b

    <u>b = 23</u>

8) \frac{2}{5} + m = \frac{5}{6} ⇒  \frac{5}{6}  - \frac{2}{5} = m

   <u>m = 13/30</u>

<u></u>

<em><u>Hope this helps!</u></em>

5 0
3 years ago
Q14
posledela

Answer:

42.6cm

Step-by-step explanation:

The sum total of all the sides of the shape is the perimeter of the shape. Hence;

Perimeter = x+3 + 4 + x+9 + 2x+5

Perimeter = 4x + 21

Given

Area of the figure = 75cm^2

Area = (x+3)(2x+5) + (2x+1)(6)

75 = 2x²+5x+6x+15+12x+6

75 =  2x²+23x+21

2x²+23x+21-75 = 0

2x²+23x-54 = 0

x = -23±√23²-4(2)(-75)/4

x = -23±√529+600/4

x = -12±√1129/4

x = -12+33.6/4

x = 21.6/4

x = 5.4

Recall that;

Perimeter = 4x+21

Perimeter = 4(5.4) + 21

Perimeter = 21.6+21

Perimeter = 42.6cm

Hence the perimeter is 42.6cm

8 0
3 years ago
Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
yaroslaw [1]

Answer: 4

Step-by-step explanation: 4 was the biggest denominator in that equation. so if we multiply by 4 on all the terms, all the denominators will go away. we will not have any more fractions!

7 0
3 years ago
Someone please help me
lina2011 [118]

Answer:

\displaystyle \boxed{\frac{60}{61}} = cos\:θ_1

Step-by-step explanation:

\displaystyle arcsin\: \frac{11}{61} ≈ 0,1813197744 \\ \\ cos\:0,1813197744 ≈ \frac{60}{61}

Since this answer is in <em>Quadrant</em><em> </em><em>I</em>,<em> </em>this would be a positive-positive answer, which in this case, will remain a positive.

<u>Extended</u><u> </u><u>Information</u><u> </u><u>on</u><u> </u><u>Quadrants</u>

\displaystyle Positive-Negative → Quadrant\:IIII \\ Negative-Negative → Quadrant\:III \\ Negative-Positive → Quadrant\:II \\ Positive-Positive → Quadrant\:I \\ \\

<u>Extended</u><u> </u><u>Information</u><u> </u><u>on</u><u> </u><u>Trigonometric</u><u> </u><u>Ratio</u><u> </u><u>Values</u>

\displaystyle y-values → sin\:θ \\ x-values → cos\:θ

I am joyous to assist you anytime.

5 0
4 years ago
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