We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
Answer:
D
Step-by-step explanation:
Answer:
Step-by-step explanation: To find the equation of the perpendicular line, take the reciprocal of the slope with the opposite sign.
For example, the reciprocal of 4/3 is 3/4 and if it's negative, the opposite is positive.
The reciprocal of 2 is 1/2. and if it's positive, the opposite is negative.
The reciprocal of any number or fraction is whatever you multiply it by to get 1. 4 times 1/4 is 1 5/4 times 4/5 is 1. What about 1 ? 1 times 1 is 1. So one is its own reciprocal!
I hope this helps. (we're not supposed to give answers to t e s t s.)
Answer:
y =(v-4)^2 -4
Step-by-step explanation:
vertex form of a parabola is
y = a (v-h)^2 +k
where (h,k) is the vertex
y =a(v-4)^2 +(-4)
y =a(v-4)^2 -4
now substitute another point in to determine a
let's pick 0, 12
12 = a((0-4)^2 -4
add 4 to each side
16 = a * (-4)^2
16 = a*16
divide by 16
a = 1
substitute in what we know
y =1 *(v-4)^2 -4
y =(v-4)^2 -4
Answer:
C
Step-by-step explanation:
y=x(1/2)^x
