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lutik1710 [3]
2 years ago
11

Which of the following vectors are orthogonal to (1,5)? Check all that apply

Mathematics
1 answer:
Andre45 [30]2 years ago
7 0
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal

</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal 

</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are  orthogonal 

<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal 

<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are  orthogonal 

the answer is 
B. (10,-2) and D. (-5,1)  are  orthogonal  to  (1,5)
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Answer:

The unknown measurement of angle R to the nearest degree is 41°

Step-by-step explanation:

As you can see, we made a diagram form the given information in the problem. We are trying to find the measurement of angle R which is our unknown angle represented by the question mark.

in order to solve this problem, we are going to be using tangent. Tangent uses the opposite side and the adjacent side from the given or from the unknown angle measurement.

So, our equation will look like this.

tanx=\frac{7.6}{8.6}

Since, we do not know the measurement of the unknown angle, then are going to use the inverse of tangent.

x=\frac{7.6}{8.6}(tan^-^1)

Now, we solve. You can use a calculator to do these calculations.

The unknown measurement of the unknown angle to the nearest degree is 41° which is answer choice D.

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An auctioneer sold a herd of cattle whose minimum weight was 920 ​pounds, median was 1160 ​pounds, standard deviation 76​, and I
katen-ka-za [31]

Answer:

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median = $565

standard deviation = $38

IQR = $48

Step-by-step explanation:

The minimum and the median are measures of location and are affected during addition (or subtraction) and multiplication (or division).

Satandard deviation and IQR (inter-quartile range), which are measures of dispersion, are affected by only multiplication (or division).

For the weight,

<em>minimum </em>= 920 pounds

<em>median </em>= 1160 pounds

<em>standard deviation</em> = 76 pounds

<em>IQR </em>= 96 pounds

For the price,

<em>minimum </em>= 0.50(920) - 15 = $445

<em>median </em>= 0.50(1160) - 15 = $565

<em>standard deviation</em> = 0.50(76) = $38............(<em>Subtraction discarded</em>)

<em>IQR </em>= 0.50(96) = $48........................................(<em>Subtraction discarded</em>)

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