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2 years ago

Which of the following vectors are orthogonal to (1,5)? Check all that apply

1 answer:

7 0

We know that
If the scalar product of two vectors is zero, both vectors are orthogonal

A. (-2,5)
(-2,5)*(1,5)-------> -2*1+5*5=23-----------> are not orthogonal

B. (10,-2)
(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal

C. (-1,-5)
(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal

D. (-5,1)
(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal

the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)

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A swim coach has at most $800 to buy equipment for the swim team. Each pull buoy costs $5.50 and each kickboard costs $10. Let x

MissTica

Answer:

5.50x+10y≤800

Step-by-step explanation:

The pull bouys are $5.50 each (5.50x)

The kickboards are $10 each (10y)

And the words "at most" mean less than or equal to

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3 0

3 years ago

Which number is the square root of 196

Elodia [21]

Hi there,

I think the answer is

14

Have a nice day

8 0

2 years ago

20 POINTS

SIZIF [17.4K]

Let get all the information.
Mean:394
Deviation:35
Looking for At Least 380 feet
To find the z score you take the wanted probality subtract the mean and divide by the deviation.
z=(380-394)/35.
z=-0.4
So far so good.
But when he looked at the table he looked at probability that the home runs are less then 380 feet.
From this table
http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf
To find the answer you have to take 1-(the probability that the home runs are less than 380 feet)or 1-0.3446=0.6554
He made an error in his calculation.

8 0

2 years ago

Read 2 more answers

Please Help!!! Evaluate the following 2/((3-(3-1))*3-1)

antiseptic1488 [7]

2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4
Then simplify again
= -1/2

6 0

3 years ago

Help with num 9 please. thanks

Alik [6]

Answer:

See Below.

Step-by-step explanation:

We want to show that the function:

$f(x) = e^x - e^{-x}$

Increases for all values of x.

A function is increasing whenever its derivative is positive.

So, find the derivative of our function:

$\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]$

Differentiate:

$\displaystyle f'(x) = e^x - (-e^{-x})$

Simplify:

$f'(x) = e^x+e^{-x}$

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of x.

8 0

3 years ago