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Kipish [7]
3 years ago
12

Find the inverse of the following. select all that apply ​

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

h^{- 1} (x) = \sqrt{(x - 8)^{3}} = (\sqrt{x - 8})^{3} = (x - 8)^{\frac{3}{2} }

Step-by-step explanation:

The given function is h(x) = \sqrt[3]{x^{2}} + 8 and we have to find the inverse function of this function h(x).

Now, let us assume, y = \sqrt[3]{x^{2}} + 8

⇒ y - 8 = \sqrt[3]{x^{2}}

⇒ (y - 8)^{3} = x^{2} {Cubing both sides}

⇒ x² = (y - 8)³

⇒ x = \sqrt{(y - 8)^{3} }

Therefore, the inverse function h^{- 1} (x) = \sqrt{(x - 8)^{3}} = (\sqrt{x - 8})^{3} = (x - 8)^{\frac{3}{2} }

So, options A, B, and D are correct. (Answer)

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Multiplying Powers with different Bases Picture Attached please help I’m on a quiz so I need the answer right
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Answer:

12800

Step-by-step explanation:

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12800

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3 years ago
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~kaikers
5 0
4 years ago
Please help me solve this problem
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1.afgx2
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7 0
3 years ago
How do I solve this ?
Allisa [31]
\left[\begin{array}{cc}3&6\\-1&-3\\-5&-1\end{array}\right] + \left[\begin{array}{cc}0&-1\\6&0\\2&3\end{array}\right] = \left[\begin{array}{cc}3+0&6-1\\-1+6&-3+0\\-5+2&-1+3\end{array}\right] = \left[\begin{array}{cc}3&5\\5&-3\\-3&2\end{array}\right]

-5\left[\begin{array}{ccc}5&6&-4\\4&-2&-1\end{array}\right] =\left[\begin{array}{ccc}-5(5)&-5(6)&-5(-4)\\-5(4)&-5(-2)&-5(-1)\end{array}\right]\\=\left[\begin{array}{ccc}-25&-30&20\\-20&10&5\end{array}\right]

4 0
3 years ago
I'd the ratio 25 to 16 proportional to the ratio 5 to 4 explain
Arturiano [62]
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3 years ago
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