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Kipish [7]
3 years ago
12

Find the inverse of the following. select all that apply ​

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

h^{- 1} (x) = \sqrt{(x - 8)^{3}} = (\sqrt{x - 8})^{3} = (x - 8)^{\frac{3}{2} }

Step-by-step explanation:

The given function is h(x) = \sqrt[3]{x^{2}} + 8 and we have to find the inverse function of this function h(x).

Now, let us assume, y = \sqrt[3]{x^{2}} + 8

⇒ y - 8 = \sqrt[3]{x^{2}}

⇒ (y - 8)^{3} = x^{2} {Cubing both sides}

⇒ x² = (y - 8)³

⇒ x = \sqrt{(y - 8)^{3} }

Therefore, the inverse function h^{- 1} (x) = \sqrt{(x - 8)^{3}} = (\sqrt{x - 8})^{3} = (x - 8)^{\frac{3}{2} }

So, options A, B, and D are correct. (Answer)

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Complete parts a through f below to find nonnegative numbers x and y that satisfy the given requirements. Give the optimum value
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Answer:

  • y = 81-x
  • the domain of P(x) is [0, 81]
  • P is maximized at (x, y) = (54, 27)

Step-by-step explanation:

<u>Given</u>

  • x plus y equals 81
  • x and y are non-negative

<u>Find</u>

  • P equals x squared y is maximized

<u>Solution</u>

a. Solve x plus y equals 81 for y.

  y equals 81 minus x

__

b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.

  P equals x squared left parenthesis 81 minus x right parenthesis

__

c. Find the domain of the function P found in part b.

  left bracket 0 comma 81 right bracket

__

d. Find dP/dx. Solve the equation dP/dx = 0.

  P = 81x² -x³

  dP/dx = 162x -3x² = 3x(54 -x) = 0

The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...

  P is maximized at (x, y) = (54, 27).

7 0
3 years ago
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