The +2 goes on the Y-Axis… From
the 2 count up 3 times and go to the right 2 times
It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds
Answer:
idk aljebra 2 either and i just got the same question how?
Step-by-step explanation:
