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neonofarm [45]
3 years ago
8

jacobs job pays him $12.50 per hour which equation can be used to find jacobs salary ,y,if he works for x hours ?

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Y = 12.5x Hope this helps!

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Andreas patio is composed of a rectangle and a semi circle as shown in the figure below which is the best estimate of the area o
Vladimir79 [104]

Answer:

38.13m²

Step-by-step explanation:

We find the area of ;

Rectangule and semicircle

Area of rectangle :

Length * width

Length = 8m ; width = 3m

Area = 8 * 3 = 24m²

Area of semicircle = 1/2 πr²

Radius, r = 3m

A = 1/2 * 3.14 * 3²

A = 1/2 * 3.14 * 9

A = 14.13 m²

Area of patio :

(24 + 14.13)m²

= 38.13m²

8 0
2 years ago
Please help with this question
Dahasolnce [82]

Answer:

10X + 20 +5X +25 = 180

15x=180-45

X= 135/15

X=9

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8 0
3 years ago
-4y+7+9y-3 identify the terms and like terms in expressions
Sliva [168]
Combine like terms
5y + 4
5 0
3 years ago
Read 2 more answers
A game has 3 possible outcomes, with probabilities p1, p2, and p3. The amount of money that you will win or lose for each outcom
Monica [59]
We have the following given
p1 - probability for outcome 1
p2 - probability for outcome 2
p3 - probability for outcome 3
v1 - amount of money that you will win or lose for outcome 1
v2 - amount of money that you will win or lose for outcome 2
v3 - amount of money that you will win or lose for outcome 3

Therefore,
p1v1 + p2v2 + p3v3 is the average money you win or lose in playing the game.
8 0
4 years ago
The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili
Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

\lambda= 4.5

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

a) No accidents occur in one week.

P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111

b) 5 or more accidents occur in a week.

P( x \geq 5) = 1-\displaystyle \sum P(x

c) One accident occurs today.

The mean number of accidents per day is given by

\lambda = \dfrac{4.5}{7} = 0.64

P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747

5 0
3 years ago
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