Ask question

Ask question

All categories

2 years ago

6

40 POINTS Geometry homework

1 answer:

kicyunya [14]2 years ago

6 0

$\angle{DBC }$ =(5x+4)°

$\angle{ A }$ =(2x-2)°

$\angle{C }$ =(4x-6)°

we know that,

$\angle{DBC}$ = $\angle{A}$ + $\angle{C}$

According to the question,

$\tt{ 5x+4=2x-2+4x-6 }$

$\tt{ 5x+4=6x-8 }$

$\tt{ 6x-5x=4+8 }$

$\blue{x=12 }$

so,

$\angle{C }$ =(4x-6)°=(4×12-6)°=(48-6)°=42°

You might be interested in

Which is a solution to the equation y=5x-6

Vilka [71]

$y=5x-6 \\ \\ the \ graph\ of \ a \ linear \ equation \ is \ a \ straight \ line$

4 0

3 years ago

Read 2 more answers

(Photo) Please help me!

SOVA2 [1]

Volume =πr²*h=π*7²*4=196π
answer B

3 0

3 years ago

Find the generating function for the sequence 1,1,1,2,3,4,5,6,....

marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

8 0

3 years ago

Which of the following is the correct graph of the linear equation below?<br> y+2 =3(x+1)

77julia77 [94]

Answer:

D

Step-by-step explanation:

3 0

2 years ago

In your own words define vertical angles

julsineya [31]

Answer:

a pair of opposite lines the are made by two intersecting lines

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers