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murzikaleks [220]

3 years ago

8

Tia’s tent is in the form of a triangular prism as shown below if Tia plans to waterproof the tent excluding the pace what is th

e area in which she will waterproof

1 answer:

Marat540 [252]3 years ago

7 0

just multiple it all together

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Lubov Fominskaja [6]

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x=4 I dont know if you are trying to find the value is x

Step-by-step explanation:

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2 years ago

Piscou possède 2021 pièces d'or. Il les répartit en piles contenant des nombres de pièces consécutifs.

anzhelika [568]

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Tom has 2,021 gold coins. He divides them into piles containing consecutive numbers of pieces. if it has more than two piles, how much is in the highest pile?

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3 years ago

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balu736 [363]

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3 years ago

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Katarina [22]

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3 years ago

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adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

5 0

3 years ago