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pychu [463]
3 years ago
12

+6\\" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

what type of math is this

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Someone please help me!
andrezito [222]
The standard form of a parabole is: (y-k) = a(x-h)², Where (h , k) are the coordinates of the vertex
In the example Vertex (3,1) ,
so (y-1) = a(x-3)². (a)
Now let's calculate a. The y-intercept coordinates(0 , 10), Replace in (a) x by 0 & y by 10:
(10-1) = a(0 - 3)²
9 = 9a and a=1
<u />The equation becomes : y-1 = (x-3)², Expand (y-1) = x²-6x+9
<u />and finally y = x² - 6x +10 (ANSWER C)
6 0
3 years ago
What expression is equivalent to the expression 2(6y-4)
Kobotan [32]

Answer:

12y-8

Step-by-step explanation:

If you distribute the 2 you will 12y-8

4 0
3 years ago
Let $f(x) = 12x^9 + x$. Find $f(3) + f(-3)$.
BlackZzzverrR [31]

Answer:

Ok, here goes:  f(3) means take f(x) and plug in 3 wherever we see x.  So

f(3) = 12*39 + 3 = 236196 + 3

f(3) = 236199

Likewise, f(-3) means take f(x) and plug in (-3) wherever we see x.  So

f(-3) = 12*(-3)9 + (-3) = -236196 - 3

f(-3) = -236199

Putting those two things together, we get

f(3) + f(-3) = 236199 - 236199 = 0

Step-by-step explanation:

7 0
2 years ago
What is the equation of this graphed line ?
yanalaym [24]
Equations of straight lines are in the form y = mx + c (m and c are numbers). m is the gradient of the line and c is the y-intercept (where the graph crosses the y-axis).
7 0
2 years ago
Read 2 more answers
Solve each system of equations algebraically. For each one, explain what the solution (or lack thereof) tells you
Paul [167]

Answer:

a: no solutions

b: (2, 3)

Step-by-step explanation:

a:

In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.

b:

Since both of the equations are equal to y, we can set them equal to each other:

\frac{1}{2}x^2+1= 2x-1\\x^2 + 2 = 4x - 2\\x^2-4x+4=0

We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):

(x-2)^2 = 0

x = 2

Now, to find y, plug-in x to any of the equations:

y = 2*2-1 = 3

Therefore, the solution to this system of equation is (2, 3)

I hope this helped.

4 0
3 years ago
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