<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%2B3%20%5C%5Cx%2B6%5C%5C" id="TexFormula1" title="x^{2}+3 \\x+6\\" alt="x^{2}+3 \\x

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pychu [463]

3 years ago

+6\\" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

6 0

Answer:

what type of math is this

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.8 repeating. I believe is this answer.

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Mrs. Miller has a rectangular garden with a length of 20 feet long with an area of (20x-200) square feet. Write an expression th

krek1111 [17]

Perimeter = (20 + 2x) mm.

Step-by-step explanation:

The octopus pupil has length 20 mm and the expression for its area is given by (20x - 200) square mm.

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2 years ago

When evaluating (6.28x10^12)/(3.14x10^4) what will be the exponent of 10 in the quotient?

alexdok [17]

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I need help with #11 - #14.

Aleonysh [2.5K]

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I can get you jump started a bit.

Step-by-step explanation:

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So let's solve the first one!

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3 years ago

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PLEASE HELP:

Lady bird [3.3K]

Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

$(x,y)\rightarrow (-y,x)$

$J(-4,1)\rightarrow J'(-1,-4)$

$K(-4,-2)\rightarrow K'(2,-4)$

$L(-3,-1)\rightarrow L'(1,-3)$

Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).

(B)

If a figure reflect across the y-axis then,

$(x,y)\rightarrow (-x,y)$

$J(-4,1)\rightarrow J''(4,1)$

$K(-4,-2)\rightarrow K''(2,-4)$

$L(-3,-1)\rightarrow L''(3,-1)$

Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).

8 0

3 years ago