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pychu [463]
3 years ago
12

+6\\" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

what type of math is this

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Find the sum. 2x^2 +26x+ 156=0
Mila [183]

Answer:

-13

Step-by-step explanation:

2x²+26x+156=0

x²+13x+78=0

x²+13x=-78

x²+13x+169/4=-143/4

(x+13/2)²=-143/4

x+13/2=(i√143)/2 or x+13/2=-(i√143)/2

x=(i√143)/2-13/2 or x=-(i√143)/2-13/2

(i√143)/2-13/2+(-(i√143)/2)-13/2=(i√143-13-i√143-13)/2=-26/2=-13

5 0
3 years ago
Read 2 more answers
A gardener wishes to design a rectangular rose garden with one side of the garden along a main road. The fencing for the 3 non-r
Reptile [31]

Answer:

There is no minimum cost for the fencing that can satisfy these conditions.

as the equation obtained for this problem is y = \frac{7x}{x-6}.

Step-by-step explanation:

let length of the rectangular rose garden be x

and breath of the rectangular rose garden be y

then the area of the garden = xy

cost of fencing a foot for the 3 non road sides = $6

and cost of fencing a foot for a road side = $8

total cost of fencing = 6x + 8x + 6y + 6y

so, total cost = 14x + 12y

cost of fencing for every square foot of the area =$2

So, 2xy = 14x + 12y

=> 2xy = 14x + 12y

Also, x and y has to satisfy x>0 and y>0

You can solve for y (or x if you prefer)

2xy-12y=14x

xy - 6y = 7x

y(x-6)=7x

y = \frac{7x}{x-6}

we can check that this function has no minimum value.

as we increase x (starting any x > 6 to make y positive) to make y minimal, y will decrease but the product xy will increase.

So, there is not a minimum cost for fencing that can satisfy these conditions.

8 0
3 years ago
Read 2 more answers
Find the height of a trapezoid if the bases have lengths of 6 and 17 and the area of the trapezoid is 46 square units.
Aleksandr [31]

Answer:

4 units

Step-by-step explanation:

The area (A) of a trapezoid is calculated using the formula

A = \frac{1}{2} h(a + b)

where h is the height and a, b the bases

here A = 46, a = 6 and b = 17, hence

46 = \frac{1}{2} h(6 + 17) ( multiply both sides by 2 )

92 = h(23) ← divide both sides by 23 )

h = \frac{92}{23} = 4 units

8 0
3 years ago
How many cubes are needed to build this structure?
Elena-2011 [213]
Hello!

I believe that 8 cubes are needed to build the given figure

I hope this helps!
6 0
3 years ago
Read 2 more answers
4 questions 20 points
Dvinal [7]
1. Cross multiply
35x = 5(11)
35x = 55
Divide both sides by 35
x = 55/35
x = 11/7

2.  (x - 2)/x = 3/8
Cross multiply
3x = 8(x - 2)
3x = 8x - 16
Subtract 8x from both sides
-5x = -16
divide both sides by -5
x = -16/-5
x = 16/5 OR  3 1/5

3.  (a + 1)/(a - 1) = 5/6
cross multiply
6(a + 1) = 5(a - 1)
distribute
6a + 6 = 5a - 5
subtract 5a from both sides
a + 6 = -5
subtract 6 from both sides
a = -11

4.  (1/3)x - 4 = (2/3)x + 6
multiply each term by 3 to clear the fractions
x - 12 = 2x + 18
subtract x from both sides
-12 = x + 18
subtract 18 from both sides
-30 = x


3 0
4 years ago
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