For this case the amplitude is given by:
A = (l-1l + 3) / 2
A = 4/2
A = 2
The middle line is given by:
y = 1
The period of the function is given by:
T = l x2 - x1 l
T = l 0 - 2pi l
T = l - 2pi l
T = 2pi
Answer:
Amplitude: 2; period: 2π; midline: y = 1
Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :
(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...<span>is the standard form of the equation
</span> <span>Select answer 1 :
</span><span>A: 3
B: 4
C: (x−3)2+(y−4)2=29</span>
Answer:
y = 8/3
Step-by-step explanation:
x = -2
y = 2/(3*-2) + 3
y = 2/-6 + 3
y = -1/3 + 3
y = -1/3 + 9/3
y = 8/3
C
Because 1 km is 1,000 meters so you were just multiply 1000 by 10 and get 10,000
c:
