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Mumz [18]
3 years ago
13

suppose a compact car uses 1 gallon of fuel for every 27 miles traveled. How would the graph for the compact car compare to the

graph for the car shown?

Mathematics
2 answers:
Gekata [30.6K]3 years ago
6 0
The answer to the question is it would add twenty seven every two times it goes up
Nezavi [6.7K]3 years ago
6 0

Answer:

1. The meaning of (2, 40) is that - when 2 gallons of fuel is used, then the distance covered will be 40 miles.

2. Equation will be :

y=20x

where y is the total distance in miles and x is the number of gallons used.

3. When we have to tell as per graph, that the car travels 27 miles in 1 gallon, the points will be : (1,27) , (2,54) , (3,81) and so on.

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The human eye is approximately spherical in shape with a radius of about 12 mm
Tom [10]

Answer:

2.3 cm if that's an option. Not sure tho

Step-by-step explanation:

Pls mark as brainliest

5 0
3 years ago
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Rewrite the rational exponent as a radical by extending the properties of integer exponents.
Aloiza [94]

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\bf \cfrac{11^{\frac{2}{5}}}{11^{\frac{1}{4}}}\implies 11^{\frac{2}{5}}\cdot 11^{-\frac{1}{4}}\implies 11^{\frac{2}{5}-\frac{1}{4}}\implies 11^{\frac{8-5}{20}}\implies 11^{\frac{3}{20}} \\\\\\ \sqrt[20]{11^3}\implies \sqrt[20]{1331}

5 0
3 years ago
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Work out the gradient of the line joining the points (2, 3) and (5,7)
Debora [2.8K]

Answer:

The gradient of the line joining the points P(x,y) = (2,3) and Q(x,y) = (5,7) is \frac{4}{3}.

Step-by-step explanation:

The gradient of the line joining two distinct point on a plane is represented by the slope of a secant line (m_{PQ}), that is:

m_{PQ} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}} (1)

If we know that P(x,y) = (2,3) and Q(x,y) = (5,7), then the gradient of the line is:

m_{PQ} = \frac{7-3}{5-2}

m_{PQ} = \frac{4}{3}

The gradient of the line joining the points P(x,y) = (2,3) and Q(x,y) = (5,7) is \frac{4}{3}.

4 0
3 years ago
9mph in still water it takes 5hrs longer to travel 74 miles upstream than downstream find the rate of current and round to neare
prohojiy [21]

Answer:

The rate of current is 2.5 mph.

Step-by-step explanation:

The speed in the water when current is absent is 9 mph.

If the speed of the current is v mph then the upstream speed is (9 - v) mph and the downstream speed is (9 + v) mph.

Now, it takes 5 hours longer to travel 74 miles upstream than down stream, then we can write the equation as  

\frac{74}{9 - v} - \frac{74}{9 + v} = 5

⇒ \frac{2v}{81 - v^{2} } = \frac{5}{74}

⇒ 148v = 405 - 5v²

⇒ 5v² + 148v - 405 = 0

Applying Sridhar Acharya's formula we can write  

v = \frac{-148 + \sqrt{148^{2} - 4(5)(-405) }  }{2(5)} (Neglecting the negative root)

⇒ v = \frac{- 148 + 173.2166}{10} = 2.5 mph (Rounded to the nearest 10th) (Answer)

7 0
3 years ago
A slide 15 feet long makes an angle of 330 with its vertical ladder. To the
Shkiper50 [21]

Answer:

13ft

Step-by-step explanation:

Kindly find attached a rough draft of the situation.

Step one:

Given data

The length of the slide represents the

Hypotenuse of the situation on the rough sketch

Angle =33°

Required

The height of the ladder which is the adjacent of the rough sketch represented by x

Step two:

Applying SOH CAH TOA

Cos θ= adj/hyp

Cos 33=x/15

0.84=x/15

Cross multiplying

x=0.84*15

x=12.6

To the nearest foot the ladder is 13ft tall

6 0
2 years ago
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