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3 years ago

A plane travels at a constant speed. It take 5 hours to travel 6,250 miles. What is the plane's speed in miles per hour?

Mathematics

1 answer:

crimeas [40]3 years ago

4 0

Answer:

1,250 miles/hour

Step-by-step explanation:

To find miles per hour - $\frac{6250 miles}{5 hours}$ .

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Please help due today

otez555 [7]

The answer is c
12.4 feet by 9.5 feet

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2 years ago

If y varies inversely with x<br> and y is 10 when x is 5,<br> then what is y when x is 2?

Jobisdone [24]

9514 1404 393

Answer:

Step-by-step explanation:

Inverse variation means ...

y = k/x

For the given values, we can find k to be ...

k = xy = (5)(10) = 50

Then for x=2, we have ...

y = 50/x

y = 50/2

y = 25 . . . when x=2

6 0

3 years ago

A single die is rolled. Find the odds in favor of rolling a number greater than 5

NeX [460]

Answer:

A die has 6 numbers.

So 6 numbers them being
1, 2, 3, 4, 5, 6

There’s only one number greater then 5 which is 6.
Since its 6 numbers, a die has a 1/6 chance of getting your desired number.

So it’s a 1/6 chance.

8 0

2 years ago

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$

c) P(completing the exam in more than 90 minutes)

P(x > 90)

$P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

$\dfrac{15.87}{100}\times 60 = 9.52\approx 10$

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0

3 years ago

What is the value of x in kite EFGH

Artyom0805 [142]

the triangle are equal and x

8 0

3 years ago