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2 years ago

The reciprocal of 7/2 is 2/7. What does that mean?

Mathematics

1 answer:

RoseWind [281]2 years ago

3 0

Answer:2/7

Step-by-step explanation: A reciprocal is the "mirror image" of a fraction so the reciprocal is the fraction upside down.

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Number 1 please <br> Add the number in each set<br> A 20,30,50,<br> B 3,9,7,4,1

Nataly [62]

Answer:

a=110 b=24

Step-by-step explanation:

7 0

2 years ago

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B) Simplify 9y - 6y + y

julsineya [31]

Answer:

The answer is 4y

Step-by-step explanation:

Simplify the expression.

Hoped this helped!

Could I perhaps get brainly?

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2 years ago

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Find the value of two numbers if their sum is 112 and their difference is 66.

snow_lady [41]

Answer:

x+y = 112 ........ (1)

x-y = 62............ (2)

from (1) and (2)

2x = 174

x = 174/2

x = 87

sub x = 87 in (1)

x+y = 112

87+y = 112

y = 112 - 87

y = 25

so the numbers are 87 and 25

Step-by-step explanation:

8 0

1 year ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

A triangle has perimeter 59 cm. The lengths of the sides are 2x – 5 cm, 3x + 2 cm and 2x – 1 cm.

Dennis_Churaev [7]

Answer:2x - 5cm + 3x +2cm + 2x - 1cm=59cm

2x + 3x + 2x + 2cm + 1cm - 5cm=59cm

7x - 2cm=59cm

7x - 2cm + 2cm=59cm + 2cm

7x=61cm

X=8 5/7cm

Step-by-step explanation:

4 0

2 years ago