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ladessa [460]
3 years ago
9

What is the volume of a rectangular prism with the dimensions: base 3 1 2 cm, height 1 1 2 cm, and length 5 1 2 cm? A) 30 1 2 cm

3 B) 28 7 8 cm3 C) 15 1 2 cm3 D) 14 7 16 cm3
Mathematics
2 answers:
e-lub [12.9K]3 years ago
4 0

Answer:

1.78913×107

Step-by-step explanation:

312·112·512≈1.78913×107

il63 [147K]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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Use Newton’s Method to find a solution of the equation e 6x+ 3(ln 2)2 e 2x− e 4x ln 8 − (ln 2)3 = 0 with error tolerance 10−5 ,
Afina-wow [57]

Answer:

  x ≈ -0.746756

Step-by-step explanation:

We have interpreted your equation to be ...

  e^{6x}+3\ln{(2)}^2e^{2x}-e^{4x\ln{(8)}}-\ln{(2)}^3=0

A graphing calculator shows the desired zero to be near -0.747. Using that value as the first guess in Newton's iteration formula, we find the next guess to be ...

  x ≈ -0.746756

Iterating another time gives a solution accurate to 12 significant digits. The above result is well within the allowed tolerance of 10^-5.

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Of course, you know that the Newton's Method iterator for finding the "next guess" is ...

  next guess = x - f(x)/f'(x)

where f'(x) is the derivative of f(x), and the value of x is the current guess.

_____

<em>Comment on this solution</em>

For the purposes of Newton's method a numerical estimate of the derivative of the function is sufficient. Most graphing calculators have a derivative function, so all you need to do is specify the function you want to evaluate the derivative of. You could go to the trouble to develop the exact formula for the derivative of this function, but it isn't necessary to obtain an answer that is close enough.

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We have shown two separate uses of the iteration function. In practice, this calculator (Desmos) gives the function result as you type the argument, so all you need to do is copy the function output to its input to obtain calculator accuracy (12 significant digits) in one pass. A calculator like a TI-84 can do a similar thing by making the first iteration, Y₂(-0.747), then repeatedly computing Y₂(Ans), that is, using the previous answer in the iteration function again. For that calculator, one additional iteration is all that is needed to get to its 10 significant digit limit.

3 0
3 years ago
Please help! I will mark brainlest! Answer the question. HELP!? Please show steps also, thank you!
mina [271]

Answer:

A

Step-by-step explanation:

reason

AM SO :)

AM SO :)

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7 0
3 years ago
Read 2 more answers
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
SVETLANKA909090 [29]
Just has to be greater than or equal to 0... w and t can never be negative since taking the square root of a negative number yields an imaginary number which would mean imaginary current. Also the question states that w can't be zero but if T is zero than the current will be zero.
3 0
3 years ago
X and Y together can do a piece of work in 10 days and X alone can do it in 15 days would Y alone can finish the work ?​
Ratling [72]

Answer:

<em>Y alone can do the piece of work in 30 days.</em>

Step-by-step explanation:

<u>Proportions</u>

Let's make:

N = days for Y to finish the work alone

Since X alone can do it in 15 days, each day he can do a proportion of 1/15 of the piece of work.

Since Y alone can (possibly) do it in N days, each day he can do 1/N parts of the work.

Together, they do

\displaystyle \frac{1}{15}+\frac{1}{N}

parts of the work per day. We know they can finish it in 10 days, thus:

\displaystyle \frac{1}{15}+\frac{1}{N}=\frac{1}{10}

Rearranging:

\displaystyle \frac{1}{N}=\frac{1}{10}-\frac{1}{15}

The LCM of 10 and 15 is 30, thus operating:

\displaystyle \frac{1}{N}=\frac{3-2}{30}=\frac{1}{30}

Solving for N:

N = 30

Y alone can do the piece of work in 30 days.

8 0
3 years ago
4 over x+4 - 2 over x+1
babymother [125]
(4/(x+4-2))/x+1

4/(x+2)=x/4+1/2

(x/4+1/2)/x+1

x=-2/5


7 0
3 years ago
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