Answer:
B and E
Step-by-step explanation:
^^^^^
Here we can change the variables to real numbers, just to make things easier for us. For the sake of calculation, let’s say that x=10, y=6, and z=1.
So, y years from now, Yann will be x years old. If we plug in our randomly chosen numbers, we get that Yann will be 10 years old 6 years from now. This means that today, he would be x-y years old, or 10-6, so 4 years old today.
Next we ask how old he was z years ago, or in this case, 1 year ago. We know that if you’re 4 years old now, you were 3 years old last year. In other words, you’re 4-1 years old, or x-y-z years old.
Your answer is x-y-z.
1.) set up a w_k_u chart
2.) in the w column write in on top and mi in the bottom like this
w_K_U
in_
mi_
then in the k column write 2 for in and 15 for mi
W_K_U
in_2_
mi_15_
then in the U column, you write 7 for in and x for mi
W_K_U
in_2_7
mi_15_x
then cross multiply: 2x = 15(7)
multiply 15 times 7 which is 105
2x=105
divide 2x by 2
x=105
answer 105
Answer: Stratified Random Sample
Hope this helps ʕ•ᴥ•ʔ
Let's pose this question a different way: what are the chances that one out of all possible events is going to happen? What are the chances that, if I roll a die, I will roll a 1, 2, 3, 4, 5, or a 6? What is the probability, if I flip a coin, that the outcome will either be heads or tails? When we take every possible outcome and add their probabilities together, the sum of the probabilities will be 100%, or 1.
Example:
Coin Toss:
Prob of Heads (.5) plus Prob of Tails (.5) = 1
Dice roll:
1/6 (odds of rolling any given number) times 6 (number of possibilities) = 1