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horrorfan [7]
3 years ago
8

What is the value of w?

Mathematics
1 answer:
natulia [17]3 years ago
3 0
This on is very easy go to my website so i can explain it better for you

 <span>https://www.youtube.com/channel/UCaxhPMTZBmFcxAZ4hYpBf_w 
</span>
Hope this 
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What is 2.23 as a fraction
sertanlavr [38]
\boxed{2.23= \frac{223}{100} } \\\\ \text{Another example:} \\ \\ 0,(4)= \frac{4}{9} \\ \\ 2,(4)= \frac{24-2}{9} = \frac{22}{9} \\ \\ 4,(16)= \frac{416-4}{99}= \frac{412}{99}  \\ \\ 1,2(3)= \frac{123-12}{90}= \frac{111}{90}  \\ \\ 2,58(936)= \frac{25893-258}{99900} = \frac{258678}{99900} \\\\ \bold{\text{Good look !!!}}
7 0
3 years ago
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Please help me with this question.<br> How can proportional reasoning help solve a problem?
andre [41]
We can use proportional reasoning to solve some questions directly, such as which size of laundry detergent is the cheapest per load, or what the dimensions of the model car should be.
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3 years ago
If tan^3(theta) -1/tan(theta)-1 - sec^2(theta) + 1 = 0 find cot(theta)
Nutka1998 [239]

\tan^3\theta-\dfrac1{\tan\theta-1}-\sec^2\theta+1=0

Recall that \tan^2\theta+1=\sec^2\theta, so we can write everything in terms of \tan\theta:

\tan^3\theta-\dfrac1{\tan\theta-1}-\tan^2\theta=0

Let x=\tan\theta, so that

x^3-\dfrac1{x-1}-x^2=0

With some rewriting we get

x^3-x^2-\dfrac1{x-1}=0

x^2(x-1)-\dfrac1{x-1}=0

\dfrac{x^2(x-1)^2-1}{x-1}=0

Clearly we cannot have x=1, or \tan\theta=1.

The numerator determines when the expression on the left reduces to 0:

x^2(x-1)^2-1=0

x^2(x-1)^2=1

\sqrt{x^2(x-1)^2}=\sqrt1

|x(x-1)|=1

x(x-1)=1\text{ or }x(x-1)=-1

Completing the square gives

x(x-1)=x^2-x=x^2-x+\dfrac14-\dfrac14=\left(x-\dfrac12\right)^2-\dfrac14

so that

\left(x-\dfrac12\right)^2=\dfrac54\text{ or }\left(x-\dfrac12\right)^2=-\dfrac34

The second equation gives no real-valued solutions because squaring any real number gives a positive real number. (I'm assuming we don't care about complex solutions.) So we're left with only

\left(x-\dfrac12\right)^2=\dfrac54

\sqrt{\left(x-\dfrac12\right)^2}=\sqrt{\dfrac54}

\left|x-\dfrac12\right|=\dfrac{\sqrt5}2

which again gives two cases,

x-\dfrac12=\dfrac{\sqrt5}2\text{ or }x-\dfrac12=-\dfrac{\sqrt5}2

x=\dfrac{1+\sqrt5}2\text{ or }x=\dfrac{1-\sqrt5}2

Then when x=\tan\theta, we can find \cot\theta by taking the reciprocal, so we get

\boxed{\cot\theta=\dfrac2{1+\sqrt5}\text{ or }\cot\theta=\dfrac2{1-\sqrt5}}

8 0
3 years ago
Please helppppp it’s due soon and I’m already failing my class!!!
Margarita [4]

Answer:

For an equation like:

y = a*x + b

a is the slope, and this is the rate of change of the function.

For the case of the problem, we know that the equation represents the amount of oxygen in the spaceship as a function of time. Where as the time passes, the quantity of oxygen decreases.

Then the slope is the rate of change that tells how the quantity of oxygen changes as time passes. Then the slope is the amount of oxygen that is consumed per unit of time.

8 0
2 years ago
Fiona found 47 pens for $3. Please help Fiona by figuring out the ratio. (round to 2 decimal places)
vitfil [10]

Answer:

c

Step-by-step explanation:

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2 years ago
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