so, x²-6x + 11, let's do some grouping first
( x² - 6x ) +11
( x² - 6x + b² ) +11
now, what's our mystery fellow "b"? well, let's recall that the middle term in a perfect square trinomial is, (a - b)² = a² - 2ab + b², so the middle term is namely just 2 times the other two fellows, without the exponent.
now, here is 6x, so then
that means, that our fellow is 3 then, so we'll add 3², however, let's keep in mind that, all we're doing is, borrowing from our very good friend Mr Zero, 0.
so if we add 3², we have to also subtract 3², therefore,
Hope it helps! Please mark me as Brainliest
Answer:
24
Step-by-step explanation:
gcf for that is 24 I think
The location of the vertex tells you the horizontal and vertical shift. (The parent function f(x) = x² has its vertex at the origin, (0, 0). The vertical distance of the point 1 unit left or right of the vertex in relation to the vertex tells you the vertical scale factor (stretch).
g(x) = f(x +3) -3
horizontal shift left 3
vertical shift down 3
h(x) = -3f(x)
reflection across the x-axis
vertical stretch of 3
d(x) = f(x -3) -3
horizontal shift right 3
vertical shift down 3
we are given to simplify
Open the bracket and write the like terms together
when the bases are same then the exponents gets added
