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2 years ago

A company's mean salary is $65,000 with a standard deviation of $6,000. If a sample of

Mathematics

2 answers:

sweet-ann [11.9K]2 years ago

8 0

Answer:

None of these

Step-by-step explanation:

math math math

7nadin3 [17]2 years ago

5 0

Answer:

umm not sure on this one either 9328.71

Step-by-step explanation:

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Which function is the inverse of f(x) = -5x -4?

Rudiy27

Answer:

f−1(x)=x5+45

Step-by-step explanation:

5 0

2 years ago

You have $2000 to deposit for 7 years and two account options. The first earns you simple interest at a rate of 4% and the secon

pogonyaev

Answer:

First account (simple interest)

Step-by-step explanation:

The amount of interest earned by the first account is ...

I = Prt = $2000·0.04·7 = $2000·0.28 = $560

The amount in the second account at the end of 7 year is ...

FV = P·(1+r)^t = $2000·1.02^7 = $2297.37

so you have earned $297.37 in interest on the second account.

$560 is more than $297, so the First Account (simple interest) earns more money.

6 0

2 years ago

What is the value of x. Please explain how you came to your answer (my other question is worth less and has a scam answer on it

Liono4ka [1.6K]

Answer:

Step-by-step explanation:

8 0

2 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

2 years ago

the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2

Ksivusya [100]

Answer:

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ .

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is $\frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1$ .

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by $b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21$ {Since $e = \frac{5}{2}$ given}

Therefore, the equation of the given hyperbola will be

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ . (Answer)

6 0

2 years ago