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postnew [5]
2 years ago
11

12x+96=h(3x+9) I need this before 4:50 pleaseee help!!

Mathematics
2 answers:
9966 [12]2 years ago
7 0
Here is your answer:

x= 3h-32
———
4-h

TEA [102]2 years ago
4 0

Answer:

x=\frac{3h-32}{4-h};      h\neq 4

hope this helps

:)

Step-by-step explanation:

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7 0
3 years ago
Combine like terms to create an equivalent expression. -1/2(-3y+10)
andrew-mc [135]

Answer:

3/2y -5

Step-by-step explanation:

-1/2 (-3y+10)

Distribute

-1/2* -3y + -1/2*10

3/2y -5

5 0
3 years ago
Read 2 more answers
Six times a number is greater than 20 more than that number. What are the possible values of that number? On-4 On>4 20 On>
Vaselesa [24]

Answer:

a > 4

Step-by-step explanation:

6a > 20 + a \\ collect \: like \: terms \\ 6a - a > 20 \\ then \: add \\ 5a \: > 20 \\ divide \: both \: sides \: by \: 5 \\  \frac{5a}{5} > \frac{20}{5} \\ a > 4

8 0
2 years ago
Graph a parabola whose vertex is at (3,5)(3,5)left parenthesis, 3, comma, 5, right parenthesis with yyy-intercept at y=1y=1y, eq
Rudik [331]

Using the given information we found that the equation of the parabola is:

y = (-4/9)*(x - 3)^2 + 5

And its graph is below.

<h3>How to get the equation of the parabola?</h3>

For a parabola with vertex (h, k), the equation is:

y = a*(x - h)^2 + k

Here the vertex is (3, 5), so the equation is:

y = a*(x - 3)^2 + 5

And the y-intercept is y = 1, this means that:

1 = a*(0 - 3)^2 + 5

1 = a*9 + 5

1 - 5 = a*9

-4/9 = a

So the parabola is:

y = (-4/9)*(x - 3)^2 + 5

And its graph is below.

If you want to learn more about parabolas, you can read:

brainly.com/question/1480401

4 0
2 years ago
In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of one half, wha
uysha [10]

The angle of sine has a value of 3/5.

Option A is the correct representation of angle sin(b°).

<h2>How do you calculate the angle b for sine?</h2>

Given that tan(b°) = 3/4 and cos(b°) = 4/5.

In trigonometry, we know that,

\dfrac {sin \theta}{cos \theta} = tan \theta

The angle of sine can be written as below.

sin \theta = cos \theta \times tan \theta

For the angle b, the above expression can be written as,

sin (b^\circ) = cos (b^\circ) \times tan (b^\circ)

Substituting the values in the above expression, we get,

sin (b^\circ) = \dfrac {3}{4} \times \dfrac {4}{5}

sin (b^\circ) = \dfrac {3}{5}

Hence we can conclude that the angle of sine has a value of 3/5.

To know more about the angle of sine, follow the link given below.

brainly.com/question/2512010.

8 0
2 years ago
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