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Svetradugi [14.3K]
3 years ago
6

In triangle ABC, the measure of the exterior angle at point B is 100°. If m∠A is 4 times larger than m∠c, FIND m∠c

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

m<c = 20º

Step-by-step explanation:

We use these following definitions:

The sum of an interior angle with its exterior is of 180º.

The sum of the three interval angles of a triangle is 180º.

The measure of the exterior angle at point B is 100°.

This means that the measure of the interior angle is: 180 - 100 = 80º

m∠A is 4 times larger than m∠c

This means that the measure of angle c is x, and the measure of angle a is 4x. The other angle, B, is 80º. So

x + 4x + 80 = 180

5x = 100

x = \frac{100}{5}

x = 20

The measure of angle C is 20º.

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Marat540 [252]

(1) The missing term in the sequence, a₁₂  = 0.8.

(2) The missing term in the sequence, a₈ = 102.5.

(3) The missing term in the sequence, a₈ = 111.

(4) The missing term in the sequence, a₁₂ = -19.

(5) The missing term in the sequence, a₁₂ = 94.

(6)  The missing term in the sequence, a₆ = 40.

(7)  The missing term in the sequence, a₃₆ = -52.

(8)  The missing term in the sequence, a₂₁ = -58.

<h3>Missing term of the sequence</h3>

The missing term in the sequence is determined as follows;

Tₙ = a + (n - 1)d

<h3>1.0 a₄ = 18.4 and a₅ = 16.2, a₁₂ = ?</h3>

T₄ = a + 3d

18.4 = a + 3d  ---(1)

T₅ = a + 4d

16.2 = a + 4d  ---(2)

subtract (1) from (2)

-2.2 = d

18.4 = a + 3(-2.2)

a = 25

a₁₂  = a + 11d

a₁₂  = 25 + 11(-2.2)

a₁₂  = 0.8

<h3>2.0 a₂ = 57.5 and a₅ = 80, a₈ = ?</h3>

a₂ = a + d

57.5 = a + d -- (1)

a₅ = a + 4d

80 = a + 4d  --- (2)

solve (1) and (2)

d = 7.5

a = 50

a₈ =  a + 7d

a₈ = 50 + 7(7.5)

a₈ = 102.5

<h3>3.0 a₁₀ = 141 and a₁₃ = 186, a₈ = ?</h3>

a₁₀ = a + 9d

141 = a + 9d --- (1)

a₁₃ = a + 12d

186 = a + 12d --- (2)

Subtract (1) from (2)

d = 15

a = 6

a₈ = a + 7d

a₈ = 6 + 7(15)

a₈ = 111

<h3>4.0 a₂₂ = -49 and a₂₅ = -58, a₁₂ = ?</h3>

a₂₂ = a + 21d

-49 = a + 21d ---- (1)

a₂₅ = a + 24d

-58 = a + 24d --- (2)

subtract (1) from (2)

d = -3

a = 14

a₁₂ = a + 11d

a₁₂ = 14 + 11(-3)

a₁₂ = -19

<h3>5.0 a₄ = -2 and a₈ = 46, a₁₂ = ?</h3>

a₄ = a + 3d

-2 = a + 3d --- (1)

a₈ = a + 7d

46 = a + 7d ---- (2)

Subtract (1) from (2)

d = 12

a = -38

a₁₂ = a + 11d

a₁₂ = -38 + 11(12)

a₁₂ = 94

<h3>6.0 a₉ = 64 and a₁₂ = 88, a₆ = ?</h3>

a₉ = a + 8d

64 = a + 8d --- (1)

a₁₂ = a + 11d

88 = a + 11d --- (2)

Subtract (1) from (2)

d = 8

a = 0

a₆ = a + 5d

a₆ = 0 + 5(8)

a₆ = 40

<h3>7.0 a₂₀ = -4 and a₂₃ = -13, a₃₆ = ?</h3>

a₂₀ = a + 19d

-4 = a + 19d ---- (1)

a₂₃ = a + 22d

-13 = a + 22d --- (2)

Subtract (1) from (2)

d = -3

a = 53

a₃₆ = a + 35d

a₃₆ = 53 + 35(-3)

a₃₆ = -52

<h3>8.0 a₂₈ = 5 and a₃₃ = 50, a₂₁ = ?</h3>

a₂₈ = a + 27d

5 = a + 27d ---- (1)

a₃₃ = a + 32d

50 = a + 32d --- (2)

Subtract (1) from (2)

d = 9

a = -238

a₂₁ = a + 20d

a₂₁ = -238 + 20(9)

a₂₁ = -58

Learn more about arithmetic progression here: brainly.com/question/6561461

#SPJ1

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