Answer:
f. the sequence goes by the half of the previous number.
= 16, 8, 4, 2, 1, 1/2, 1/4, 1/8...
g. the sequence goes by adding the consecutive odd number added to the previous number.
first number= 3.
second number= 3+3
= 6
third number= 6+5
= 11
fourth number= 11+7
= 18
fifth number= 18+9
= 27
sixth number= 27+11
= 38
seventh number= 38+13
= 51, etc.
= 3, 6, 11, 18, 27, 38, 51...
Answer:
1+1 = 1111111111111111111111
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
7x+(x-4)(X+5)-5x
7x+(X*2+ 5x-4x-20)-5x
7x+(X*2+ x-20)-5x
X*2+3x-20
The customer pays $85 because 10.15 multiplied by 8.375 equals 85.00625 or $85 hope that helps!