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3 years ago

Please answer the following, 50 points available!

Mathematics

2 answers:

Rus_ich [418]3 years ago

6 0

Answer for Area:

6,518.75 square meters

Explanation for Area:

First, you would multiply the length and the width of the car park to find its area (75 x 100 =7500). Now, find the area of the arena. Since you are given the diameter, divide it by 2 to get the radius (25). Now multiply π by 25^2. This should give you 1962.5. Then, since only half of the arena is in the car park, divide the area of the arena by 2. Now you have 981.25. Now, subtract this from the area of the car park (7500). Your answer should now be 6,518.75.

Answer for Fence:

295 meters

Explanation for Fence:

Add up all the sides. There are two sides with 100 meters and 2 sides with 75 meters. But, because you arent supposed to include the space where the arena is. only add 25. This gets you 300. Now, subtract 5 meters for a gate. 295 is your final answer.

Mila [183]3 years ago

4 0

Answer:

6,518.75 square meters

Step-by-step explanation:

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A carpenter cut out a small trapezoid as a wooden support for the front step. it has an altitude of 4 inches. One base of the tr

docker41 [41]

Area of wooden support is 36 square inches

Solution:

Given that, carpenter cut out a small trapezoid as a wooden support for the front step

The area of trapezoid is given as:

$area = \frac{a+b}{2} \times h$

Where, "h" is the height

"a" and 'b" are the length of base

Here given that,

Height = h = 4 inches

a = 6 inches

b = 12 inches

Substituting the values we get,

$area = \frac{6+12}{2} \times 4\\\\area = 18 \times 2\\\\area = 36$

Thus area of wooden support is 36 square inches

6 0

4 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

Someone knows this one? help me please help help :( thank you so much

noname [10]

Answer: d

Step-by-step explanation:

$KE=\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=\bigg(\dfrac{2}{m}\bigg)\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=v^2\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=\sqrt{v^2}\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=v$