Answer: approximately 24
Step-by-step explanation:
We need to plot a regression line.
So we fit a model using the regression of Y on X, that an equation that predict Y for a given X using:
(Y -mean(Y ))= a(X-meanX)...........1
Where the formular of a is given the attachment.
N= the of individuals = 5
Y = amount of fat
X = time of exercise
mean(X )= sum of all X /N
= 131/5 = 26.2
mean(Y) = sum of all Y/N
= 104/5 = 20.8
a = N(SXY) - (SX)(SY)/ NS(X²) -(SX)²......2
SXY = Sum of Product X and Y
SX= sum of all X
SY = Sum of all Y
S(X²)= sum of all X²
(SX) = square of sum of X
a = -0.478
Hence we substitute into 1
Y-20.8 = -0.478 (X-26.2)
Y -20.8 = -0.478X - 12.524
Y = -0.478X + 33.324 or
Y = 33.324 - 0.478X (model)
When X = 20
Y = 33.324 - 0.478 × 20
Y = 33.324 - 9.56
Y = 23. 764
Y =24(approximately)
Carefully meaning of formula used in attachment to the solution they are the same.
Answer:
Scale factor = 7
Step-by-step explanation:
Dilation with scale factor to map HEFG to DABC will be,
Scale factor = 
= 
Length of CD = Distance between two points C(0, -7) and D(-7, 0)
= 
= 
= 
= 
Length of GH = Distance between G(0, -1) and H(-1, 0)
= 
= 
Scale factor = 
= 7
Answer:
2xy(x+5)(4x−1)
Step-by-step explanation:
1 Find the Greatest Common Factor (GCF).
GCF = 2xy
2 Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
2xy (8x^3y + 38x^2y/2xy + −10xy/2xy)
3 Simplify each term in parentheses.
2xy(4x^2 +19x−5)
4 Split the second term in 4x^2+19x-5 into two terms.
2xy(4x^2 +20x−x−5)
5 Factor out common terms in the first two terms, then in the last two terms.
2xy(4x(x+5)−(x+5))
6 Factor out the common term x+5.
2xy(x+5)(4x−1)
Answer:
Step-by-step explanation:
y = -x-3
y = x^2 + 4x + 1
x^2 + 4x + 1 = -x-3
x^2 + 5x + 4 = 0
Quadratic Formula
x = [-5±√(5²-4⋅1⋅4)]/[2⋅1] = [-5±√9]/2 = [-5±3]/2 = 1,-4
(x,y) = (1,-4) of(-4,1)
Answer:
research it many my answer will be wrong
