Question

4. The regression line for this bivariate data set is = 19.41 + .17x. What is the residual for the point with an x-value of 68? x 56 45 68 49 58 63 66 62 y 28 25 34 30 32 36 23 29

Answer 1

Answer:

3.03

Step-by-step explanation:

x y

 

56 28

45 25

68 34

49 30

58 32

63 36

66 23

62 29

 

slope 0.174993175

Intercept 19.40977341

$y=19.41+0.17x$

is the regression line

As per line, we can find y for x=68 as

$y(68) = 19.41+0.17(68)\\= 30.97$

For x=68

y actual = 34

y predicted = 30.97

Residual = 34-30.97

= 3.03