All categories

3 years ago

Find the measures of the four numbered angles

Mathematics

1 answer:

Genrish500 [490]3 years ago

5 0

First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65

You might be interested in

Please Answer these ASAP Find the area.

mestny [16]

Answer:

polygon is regular. Round answer to the nearest tenth

Step-by-step explanation:

$36 - 6 \times = \frac{ < \sqrt{ \geqslant \binom{ | |4)6300 \times - 9x55.90660606.. \sqrt{. \geqslant 522 \sqrt[25h \\ ]{?} \times \frac{?}{?} \times \frac{?}{?} } | | \times \frac{?}{?} }{?} } }{?} \times \frac{?}{?}$

8 0

3 years ago

Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s

lakkis [162]

Answer:

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2. Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

8 0

3 years ago

Read 3 more answers

If an unfair coin comes up heads 60% of the time and tails 40% of the time, what is the expectation if heads is valued at 1 a

monitta

I would think the value would be .2 cause if you had 100 tosses you would expect 60 value for heads and -40 value for tails. giving you 20/100

5 0

3 years ago

1.) Evaluate the indicated function, where f(x) = x2 − 8x + 3and g(x) = 7x − 5.

noname [10]

Answer:

1) (f + g) (5) = 18, 2) (f + g) (1/2) = - 13/4, 3) (f - g) (-1) = 14, 4) (f * g) (7) = 456, 5) (f/g) (- 2) = - 3/4, 6) (g ○ f)(x) = 6 x - 23, (f ○ g)(x) = 6 x - 6, 7) $(g \circ f) (x) = \frac{9}{x} - 24$ , $(f \circ g) (x) = \frac{1}{x - 2} + 5$ , 8) (f ○ g)(5) = 3

Step-by-step explanation:

1) $(f + g) (x) = x^{2}-8\cdot x + 3 + 7 \cdot x - 5\\(f + g) (x) = x^{2} - x - 2\\(f + g) (5) = 18$

2) $(f + g) (x) = x^{2} - 7 \cdot x + 4 + 6 \cdot x - 7\\(f + g) (x) = x^{2} - x - 3\\(f + g) (\frac{1}{2} ) = - \frac{13}{4}$

3) $(f - g) (x) = x^{2} - 3 \cdot x + 4 - 4 \cdot x + 2\\(f - g) (x) = x^{2} - 7 \cdot x + 6\\(f - g) (-1) = 14$

4) $(f \cdot g) (x) = (x^{2}-4\cdot x + 3) \cdot (3\cdot x - 2)\\(f \cdot g) (7) = 456$

5) $(f / g) (x) = \frac{x^{2}-3\cdot x + 2}{4 \cdot x - 8} \\(f / g) (-2) = - \frac{3}{4}$

6) $(g \circ f) (x) = 3 \cdot (2 \cdot x - 8) + 1\\(g \circ f) (x) = 6 \cdot x - 23\\(f \circ g) (x) = 2 \cdot (3 \cdot x + 1) - 8\\(f \circ g) (x) = 6 \cdot x - 6$

7) $(g \circ f) (x) = 3 \cdot (\frac{3}{x} - 6) - 6\\(g \circ f) (x) = \frac{9}{x} - 24\\(f \circ g) (x) = \frac{3}{3 \cdot x - 6} + 5\\(f \circ g) (x) = \frac{1}{x - 2} + 5$

8) $(f \circ g) (x) = 2 \cdot (x^{2} - 5 \cdot x) + 3\\(f \circ g) (x) = 2 \cdot x ^{2} - 10 \cdot x + 3\\(f \circ g) (5) = 3$

3 0

3 years ago

Please and thank you

liraira [26]

Answer:

its the root 11

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers