Answer:
Step-by-step explanation:
QM is the angle bisector of ∠LMP
∠LMQ = ∠QMP
QM is the angle bisector of ∠PQL
∠PQM = ∠MQL
MQ = QM as common
By ASA, triangle MQP ≅ MQL
LM = PM and LQ = PQ as they are same side of congruent triangles
Triangle LPQ and LPM are isosceles
By angle bisector theorem, LP is perpendicular to MQ
By properties of rhombus, the two diagonals are perpendicular proves that LMPQ is a rhombus.
LM ≅ PQ
Answer:
Below.
Step-by-step explanation:
Perimeter = 2(2x + 7 + 3x + 8)
= 2(5x + 15)
= 10x + 30.
Pick the third one because he tell you which graph represents a bike traveling at constant rate of 12 miles per hour
3 7/8 because looking at the ruler, the line is 7 of the 8. hope that’s helps!
In the attachement, there is what I came up with so far. I think that finding 'a' is non-trivial, if possible at all.
- the area of a circle
- the area of a circular segment
