Question

Starting at home Omar traveled a pill to the gift store for 30 minutes such as 10 mph event travels back home along the same path down hill at a speed of 30 mph what is his average speed for the entire trip from home to the gift store and back

Answer 1

We know Distance formula is  Distance = speed * time

$time = \frac{distance}{speed}$

Let, the distance Omar traveled = d  and speed is 10 miles per hour

Time taken  t for the first trip  $t = \frac{d}{10}$

Let, the distance Omar traveled = d  and speed is 30 miles per hour

Time taken  t for the return  trip  $t = \frac{d}{30}$

Total time taken =  $\frac{d}{10} + \frac{d}{30} = \frac{3d+d}{30} = \frac{4d}{30}$

Now, $Average \ speed = \frac{total \ distance}{total \ time \ taken}$

Total distance = d+d= 2d

Average speed = $\frac{2d}{\frac{4d}{30}}$ = $2d * \frac{30}{4d} = 15$

His average speed for the entire trip from home to the gift store and back is

15 miles per hour