Two<span> trains </span>leave different<span> cities heading toward each </span>other<span> at </span>different<span> speeds. ... At the </span>same time<span>Train B, </span>traveling 60 mph<span>, leaves Eastford heading toward Westford. ... Since an equation remains true as </span>long<span> as we perform the </span>same<span> operation ... that the train's rate is 40 </span>mph<span>, which means it </span>will travel<span> 40 </span>miles<span> in </span>one<span> hour.</span>
Answer:
Step-by-step explanation:
Notice that the y-component is the same, -2, in these two points. That means y does not change as x changes, and therefore we conclude that the slope of the line connecting the two points is m = rise / run = 0.
-2 - (-2)
Alternatively, use m = -------------- = 0
3 - 13
The value of the slope in question is zero: m = 0
Answer:
4
Step-by-step explanation:
Answer:
wow i have never seen that instrument before.
Step-by-step explanation:
Question 1
Let the scale factor be k.
Then, we have the mapping

This implies that:

We equate any corresponding component find the value of the scale factor k.
6k=2


Hence the scale factor is 
Question 2:
The midpoint of any two points can be calculated using the formula;

We want to find the midpoint of (-8, 5) and (2, -2).


The midpoint is:
