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natima [27]
2 years ago
13

For the function find f-1(x)

Mathematics
2 answers:
Svetach [21]2 years ago
8 0
The answer is C. i know because i looked it up
Mkey [24]2 years ago
6 0

since you know that to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solve for "y".

\stackrel{f(x)}{y}=\sqrt[3]{\cfrac{x+6}{2}}\implies \stackrel{\textit{quick switcheroo}}{x=\sqrt[3]{\cfrac{y+6}{2}}}\implies \stackrel{\textit{cubing both sides}}{x^3=\cfrac{y+6}{2}} \\\\\\ 2x^3=y+6\implies 2x^3-6=\stackrel{f^{-1}(x)}{y}

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The triangle will still be similar to the original triangle.
Those transformations altered the position and scale of the triangle, but the angle measures are still the same.
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Why is isolating the y-variable to graph is important
dusya [7]

Answer:

It is the easiest way to graph an equation.

Step-by-step explanation:

Isolating the y variable is also slope-intercept form.

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it makes it way easier to graph an equation when it is in slope intercept form.


I hope that helps! =)

6 0
3 years ago
Write an equation of the line that passes through (2, -3) and is perpendicular to the line y=-2x-3
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Answer:

y=\frac{1}{2} (x-2)-3 or y=\frac{1}{2} x-4

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Write the equation in point-slope form (y=a(x-h)+k):

y=\frac{1}{2} (x-2)-3

Convert to slope-intercept form if needed:

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The formula is m=4a+2c where c is the number of children, m=the number of meatballs, a=number of adults.
Trava [24]

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A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p
gizmo_the_mogwai [7]

Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

Since is a bilateral test the p value would be:

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0
3 years ago
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