Did you solve this? I need it too.
Answer:
I answered your last question also
2 log3x – 2 logx3 -3 <0
Step-by-step explanation:
V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
Percent change = (new number - old number)/(old number) * 100
percent change = (54 - 48)/(48) * 100 = 6/48 * 100 = 0.125 * 100 = 12.5%