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kicyunya [14]
3 years ago
11

Can I please get help with 2 and 8

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
6 0

Answer:

2=    P=C*1.50-(C*.3)-20

Idk what 8 is though

Step-by-step explanation:

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What’s the answer? Please help!
Gelneren [198K]

Answer:

B

Step-by-step explanation:

(2\sqrt{27})\cdot (3\sqrt{32})= \\\\(6\sqrt{3})\cdot (12\sqrt{2})= \\\\(6\cdot 12) \cdot (\sqrt{3} \cdot \sqrt{2})= \\\\72\sqrt{6}

Hope this helps!

8 0
3 years ago
Read 2 more answers
PLEASE ANSWER
Sonja [21]

Answer:

Step-by-step explanation:

8 0
3 years ago
Does (-2x+y=6)+ (y-2x=4) have no solution?
DedPeter [7]
Assuming you are asking

does -2x+y=6 and y-2x=4 have a solution

look at them
rewrite first equation by switching x and y
y-2x=6 and
y-2x=4
false since they are same values

there is no solution
these 2 lines are paralell

NO SOLUTION
4 0
4 years ago
Simplify this expression.
Bond [772]

The correct expression to simplify is:

1+4.25n + 3/2p -3+(-2p)+5/4n

Answer:

5.5n-1/2p-2

Explanation:

<u>1. Given expression</u>:

1+4.25n + 3/2p -3+(-2p)+5/4n

<u>2. Group like terms</u>:

(1-3)+(4.25n+5/4n)+(3/2p-2p)

<u>3. Simplify</u>:

  • 1 - 3 = - 2
  • 4.25n + 5/4n = 4.25n + 1.25n = 5.5n
  • 3/2p - 2p = 1.5p - 2p = - 0.5p = - 1/2p

-2+5.5n-1/2p=5.5n-1/2p-2

8 0
4 years ago
Cos^2(2theta)+ 2cos(2theta)+1=0
Tema [17]

Answer:

θ = π n + π/2 for n element Z

Step-by-step explanation:

Solve for θ:

1 + 2 cos(2 θ) + cos^2(2 θ) = 0

Write the left hand side as a square:

(cos(2 θ) + 1)^2 = 0

Take the square root of both sides:

cos(2 θ) + 1 = 0

Subtract 1 from both sides:

cos(2 θ) = -1

Take the inverse cosine of both sides:

2 θ = 2 π n + π for n element Z

Divide both sides by 2:

Answer:  θ = π n + π/2 for n element Z

4 0
3 years ago
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