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madam [21]
3 years ago
6

19/24 as a decimal rounded to the nearest hundredth

Mathematics
2 answers:
borishaifa [10]3 years ago
8 0

Answer:

0.79

Step-by-step explanation:

Pachacha [2.7K]3 years ago
3 0

Answer:

.79

Step-by-step explanation:

19/24

is about .79166666 repeated

rounded to the nearest hundredth is .79

since you remain the same if the next place value is less than 5

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Can someone help me out with these problems and show work please !!
AVprozaik [17]

Answer:

13. 10a^4b²

14. -5y³ + 35y² - 10y

Step-by-step explanation:

Question 13:

(5a³b) (2ab) =

=10a^4b²

Question 14:

5y (-y² + 7y - 2) =

= -5y³ + 35y² - 10y

Hope this helps!

5 0
2 years ago
a parallelogram has one angle that measures 40. what are the measures of the other three angles in the parallelogram?
KonstantinChe [14]
Since one side is 40°, you subtract that from 180.

180° - 40°= 140°.

So therefore your missing side lengths are 140, 40, and 140.

hopefully this helps





6 0
3 years ago
Read 2 more answers
find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
2 years ago
What is the equation of the line that passes through the point (-1, 4) and has a<br> slope of -5?
AfilCa [17]

Answer:

Step-by-step explanation:

y - 4 = -5(x + 1)

y - 4 = -5x - 5

y = -5x - 1

4 0
3 years ago
|3x| = 9<br> Variable please.
Lorico [155]

Answer:

x = 3 or x = -3

Step-by-step explanation:

The absolute value of 3x = 9

Divide nine by 3 to get 3

Absolute value represents the number of spaces an integer is from 0, so the answer could also be -3, as the absolute value of 3 x -3   (-9) is 9.

7 0
3 years ago
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