I'm in seventh grade. I haven't learned that yet.
try asking your teacher.
Answer:
the last one talking about victoria has y dollars
Step-by-step explanation:
x times 12 is equal to y, so the equation is y = 12x
Answer:
This is the equation for cellular respiration.
Step-by-step explanation:
C6H1206 is glucose. O2 is oxygen. They react to produce 6H20, which is water, and 6CO2, which is carbon dioxide. Energy is also produced which is represented by 2800 kJ. Energy is created in the form of ATP and heat.
The graph that shows the solutions for the inequality, y > -1/3x + 1 is: C. Graph A.
<h3>How to Find the Graph of a Linear Inequality?</h3>
The inequality sign, ">" means that the graph of the inequality has a dashed line where the shaded part is above the boundary line and the boundary line is dashed or dotted. If "≥" is used, the boundary line would not be dashed or dotted and the shaded area would be above it.
On the other hand, "<" is used when the shaded area is below the boundary line and the boundary line is a dashed line. If "≤" was used, the boundary line won't be dashed or dotted, while the shaded area would be below the boundary line that is not dotted.
Given y > -1/3x + 1, the slope (m) = change in y / change in x is -1/3.
Graph A has a slope of -1/3 and the shaded part is above the boundary line.
Therefore, the graph that shows the solutions for y > -1/3x + 1 is: C. Graph A.
Learn more about inequality graph on:
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Deposited amount = $14.
Rate of interest = 2.7%
In decimals 2.7 could be written by dividing 2.7 by 100, we get
0.027.
Interest earned each year = 2.7% of $14 = 0.027*14 = $0.378.
We can make a table to balance by after each year.
First year balance: First year interest + Deposited amount = 0.378 +14 = $14.378.
Second year balance: Second year interest + Deposited amount = 2*0.378 +14 = 0.756+ 14 = $14.756.
Third year balance: Third year interest + Deposited amount = 3*0.378 +14 = 1.134+ 14 = $15.134.
We get four coordinates to graph A(0,14), B(1, 14.378) , C(2, 14.756) and D(3, 15.134).
Plotting those coordinates of the points A, B, C and D on the graph.
