Law of sines and the law of cosines

Mathematics

1 answer:

Artyom0805 [142]3 years ago

8 0

You would need to use the law of cosines, which is c^2=a^2+b^2-2ab(CosC) , if you are looking for the angles.

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insert grouping symbols to make the answer correct. Then evaluate the expression to justify your work. 9 + 3 • 4 - 6 + 12 / 3 =

Lena [83]

9 + (3 x 4) - 6 + 12/3 3 makes 12 4 times which is why 12/3 is 4
9 + 12. -6. +. 4
21 - 6 + 4
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3 years ago

Name the property:

Neporo4naja [7]

Answer:

B. Commutative Property of Multiplication

Step-by-step explanation:

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2 years ago

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<img src="https://tex.z-dn.net/?f=-3%2Fz%2B7%2F4z%3D5%2Fz-25" id="TexFormula1" title="-3/z+7/4z=5/z-25" alt="-3/z+7/4z=5/z-25" a

ycow [4]

Answer:

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Step-by-step explanation:

See attached image

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2 years ago

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Please someone help please pls

mario62 [17]

Answer:

h= $h= \frac{5R^{3} }{LU}$

Step-by-step explanation:

1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is $\frac{1}{L}$ .....So it would look like:

$(\frac{1}{L} )*\frac{5R^{3} }{U} = \frac{L}{h}* (\frac{1}{h} )\\$

2.) Simplify the equation if you need to (in this case, its not needed)

$\frac{5R^3}{LU} =h$

That's your answer :)

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3 years ago

nickel has an approximate diameter of 20 mm and an approximate thickness of 2 mm what is the approximate volume of a stack of 40

ziro4ka [17]

Answer:

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

Step-by-step explanation:

A nickel can be modelled by the formula of a right cylinder, the approximate volume of the stack of nickels ( $V_{net}$ ), measured in cubic milimeters, is the product of the number of elements ( $n$ ), no unit, and the volume of each element ( $V$ ), measured in cubic milimeters. That is: