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aivan3 [116]
3 years ago
11

Hi I'm just doing my homework and I need help if you got the answer tell me how you got it

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
For this question the answer would be letter d
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Liam is setting up folding chairs for a meeting. If he arranges the chairs in 6 rows of the same length, he has 11 chairs left o
uranmaximum [27]

Answer:

25

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
These data can be approximated quite well by a N(3.4, 3.1) model. Economists become alarmed when productivity decreases. Accordi
CaHeK987 [17]

Answer:

First part

P(X< 3.4-0.6*3.1) = P(X

And for this case we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And using this formula we got:

P(X

And we can use the normal standard table or excel and we got:

P(Z

Second part

For the other part of the question we want to find the following probability:

P(-1.715

And using the score we got:

P(-1.715

And we can find this probability with this difference:

P(-1.65< Z< 1.210)=P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the data of a population, and for this case we know the distribution for X is given by:

X \sim N(3.4,3.1)  

Where \mu=3.4 and \sigma=3.1

First part

And for this case we want this probability:

P(X< 3.4-0.6*3.1) = P(X

And for this case we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And using this formula we got:

P(X

And we can use the normal standard table or excel and we got:

P(Z

Second part

For the other part of the question we want to find the following probability:

P(-1.715

And using the score we got:

P(-1.715

And we can find this probability with this difference:

P(-1.65< Z< 1.210)=P(Z

8 0
3 years ago
A bus went halfway from a village to a city at a certain speed. Then it stopped in traffic for an hour. In order to catch up the
k0ka [10]
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.

Since 200 km is "halfway", the total distance must be 400 km.

time = distance / speed
total time = (time for first half) + (delay) + (time for second half)

400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40

The speed of the bus before the traffic holdup was 40 km/h.
4 0
3 years ago
What is the significant figure
11Alexandr11 [23.1K]
Im pretty sure for number 14. 4.302 is correct and number fifteen is 6.37 i’m not sure though, sorry
7 0
2 years ago
0.2) Sharad bought one quintal of onions for Rs 2000. Later he
dalvyx [7]

Answer: Loss, 200 Rs

Step-by-step explanation:

Given

Sharad bought  a quintal of onion i.e. 1000\ kg for Rs.\ 2000

So, the cost price of onion is

\Rightarrow \dfrac{2000}{100}=20\ \text{Rs per kg}

He sells it at 18\ \text{Rs. per kg}

Here, the Selling price is less than the cost price

So, he incurs a loss of 2\ \text{Rs per kg}

For a quintal it is

\Rightarrow 2\times 100=200\ \text{Rs}

\Rightarrow \text{Loss }\ \%=\dfrac{C.P.-S.P.}{C.P.}\times 100\\\\\Rightarrow \text{Loss }\ \%=\dfrac{20-18}{20}\times 100=10\%

6 0
3 years ago
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