Sure! Let's do this in order.
First, we can simplify the left side with the distributive property, getting us
8c-14
Next, we can simplify the right side with the distributive property, getting us
8c-8-6.
That gives us 8c-14<8c-8-6.
We can subtract 8c from both sides, getting us
-14<-8-6
Simplify the right side to get
-14<-14
This inequality has no solution. This is because the variable is gone, and the remaining equation isn't true.
Answer:
Step-by-step explanation:
the first method :
s(x) = 2 - x and f(x) = 3x
(s f) (-7) = s(-7) ×f(-7)
but : s(-7) = 2 - (-7) =2+7 = 9
f(-7) = 3(-7) = - 21
so : (s f) (-7) = (9)×(-21) = - 189
the second method :
calculate : (s f) (x) == s(x)×f(x) = (2-x) 3x = 6x - 3x²
(s f) (-7) = 6(-7) -3 (-7)² = - 42 -147 = -189
Answer: The polynomial that describes the projectile's height is:
P(t) = - 16t*2 + 300t
For t = 1 second we have:
P(1) = - 16*1^2 + 300*1
P(1) = 284 ft
The height of the projectile after 1 second is 284 feet.
Step-by-step explanation:
I would compute sqrt(1 + 160pi^2) first to get approximately 39.75093337
Add this to 1 and we have 40.75093337
Then divide over 2pi to get a final approximate result of 6.48571248
So x = 6.48571248 is one approximate solution
In short, I computed 
only focusing on the plus for now.
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If you were to compute 
you should get roughly -6.167402596 as your other solution. Each solution can then be plugged into the original equation to check if you get 0 or not. You likely won't land exactly on 0 but you'll get close enough.
