f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
no real solutions
complex solutions: x = 0.5±i√10.75, y = -2.5±i·3√10.75
Step-by-step explanation:
The graph shows the line and parabola do not intersect, so there are no real solutions to this system of equations.
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However, the complex x-solutions can be determined from the graph to be ...
x = 0.5 ±i√10.75
The corresponding y-values can be found from the equation
y = 3x -4 = 3(0.5 ±i√10.75) -4
y = -2.5 ± i·3√10.75
Answer: The distribution has an outlier
Step-by-step explanation: If you look at the graph you can clearly see it is the only one really off to the side even without doing any math.
The expression that can be used to find the area of the tiled floor is 4w² + 200w
<h3>Area of rectangle</h3>
Length = 70 Meters
Width = 30 meters
Area = length × width
= 70 × 30
= 2100
- New rectangle(including tiled floor):
Length = 70 + 2w meters
Width = 30 + 2w meters
Area = length × width
= (70+2w) (30+2w)
= 2100 + 140w + 60w + 4w²
= 4w² + 200w + 2100
Area of the tiled floor = Area of new rectangle - area of old rectangle
= (4w² + 200w + 2100) - 2100
= 4w² + 200w + 2100 - 2100
= 4w² + 200w
Learn more about area of rectangle:
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