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3 years ago

Here’s an update someone helped me get this and it didn’t work

Mathematics

1 answer:

AfilCa [17]3 years ago

5 0

Answer:

Left side

Ca(OH)2 --> Ca + 2 O + 2 H

2 HBr --> 2 H + 2 Br

Together: Ca + 2 O + 4 H + 2 Br

You have only 1 Br and only 3 H. So you must correct this.

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Can anyone please help me with this?

marin [14]

Answer:

I believe that It would be b

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3 years ago

John has a round swimming pool.The distance from the center of the pool to the edge is 3 meters.What is the diameter of John poo

shtirl [24]

Answer:

6 meters

Step-by-step explanation:

Th equation to find the diameter of a circle is,

radius * 2.

The radius of the swimming pool is 3, so 3 * 2 is 6.

Hope this helps!!

Let me know if I'm wrong...

8 0

3 years ago

4. a. On the grid, draw at least three different quadrilaterals that can each be

Julli [10]

Answer:

this is just for part A sorry i dont get part B

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4 0

4 years ago

3/5x=52 is the answer 120 or 130

postnew [5]

The direct answer to your question is: "No".
because in that equation, 'x' is not 120 or130.

Let's find out what 'x' actually is:

3/5 x = 52

Multiply each side by 5 : 3x = 260

Divide each side by 3 :  x = 86 and 2/3 

8 0

4 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

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