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2 years ago

I need help on this question plz help plz

Mathematics

1 answer:

love history [14]2 years ago

3 0

Answer: The equation would be W = 500 + 30T

Step-by-step explanation: The variables given are, W which represents the amount of water, and T which represents the time in minutes that water has been added. Already there is 500 liters in the water tank to start with, that means as you begin to add water, its simply an addition to the already existing 500 liters, (that is + 500).

Also you are told that you can add water at a rate of 30 liters per minute, that is you have one T for every 30 (or simply put 30T).

Therefore the equation that correctly relates W to T is shown as;

W = 30T + 500

With this, your table of values would now be shown as;

x = 1, y =530

x= 2, y = 560

x = 3, y = 590

x = 4, y = 620

x = 5, y= 650

Then your graph is as shown in the image attached.

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Fynjy0 [20]

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4 0

3 years ago

2/5 of the children in a club are girls,if there are 24 boys,how many children are there altogether?how many more boys than girl

Masja [62]

2/5 are girls, therefore 3/5 are boys

3/5 = 24
1/5 = 24 ÷ 3 = 8
2/5 = 8 x 2 = 16

Altogether = 16 + 24 = 40

24 - 1 6 = 8

There are 40 children altogether
There are 8 more boys than girls.

5 0

3 years ago

Read 2 more answers

Question:

prohojiy [21]

Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!

4 0

3 years ago

Identify the type of function represented by each graph

mario62 [17]

Answer:

13. Linear Function

12. Absolute Value Function

11. Quadratic Function

10. Constant and Linear Function

Step-by-step explanation:

13. This graph is in Slope-Intercept Form, $y = mx + b$ . The equation of this line is $y = x + 1$ .

12. This graph obviously is an Absolute Value graph because it is in the shape of a "V".

11. This graph is in the shape of a parabola, so it is considered "Quadratic".

10. This line is constant because it is a horizontal line, but it is ALSO considered a linear function because it is in the form of $y = mx + b$ , and the equation of this line is $y = -2$ , where you have NO rate of change [slope]. This is what you call horizontal lines, zero slopes.

I am joyous to assist you anytime.

6 0

3 years ago

Find the equation of the line passing through the points (5,21) and (-5,-29)

Assoli18 [71]

Answer:

Look below

Step-by-step explanation:

lets have -29 be y2 and -5 be x2

21 - (-)29

5 - (-)5

Subtracting a negative is just adding it so

21 + 29 50
5 + 5 10

50/10

this simplified, is 5/1 or 5

y=5x+b

now we need to find b, so we substitute y and y

x = 5

y = 21

21=5*5=b

5*5 is 25

now we need to get to 21

25 -4 is 21

b = -4

y=5x-4

3 0

2 years ago