$\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}$

6 0

3 years ago

If you do these ill give brainliest!! someone smart please help. im struggling

IRISSAK [1]

ANSWER:
15
32
31
10
23
6.5
35
4.8
63
66
200
72
Solution:
Say you have a triangle that is 2.5 by 1
The Number that comes first is the base and there’s only one bass and there’s two sides in those size are 1 so 1×2 is 2+2.5=4.5 so all you’re doing is adding up all the sides together on any shape

4 0

3 years ago

Perpendicular lines are defined as

BartSMP [9]

Lines that overlap each other opposite like a T or +

6 0

3 years ago

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