We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem.
We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:
at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8
for the second equation
at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6
we group the points based on their original corresponding t's
(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
Answer: hopes this helps i spent a lot of time on it !!!:)lol
2
0
+
3
6
−
8
−
1
2
2
0
+
1
0
1
0
ℎ
−
1
5
−
1
2
−
1
4
5
6
−
6
3
8
−
1
8
−
8
+
1
2
Step-by-step explanation:
Function g takes 4 as input and return 2 as output
f takes input 2 and returns output 4
from the graph
g(4)=2
f(2)=4
Since the divisor is 2 digits, start by looking at the first 2 digits of the dividend. Those are 44, so you're dividing 44 by 15 at the first step. The quotient digit is the largest integer that gives a value less than or equal to the dividend (44) when multiplied by the divisor (15). For the first step, that digit is 2.
To find the new divisor, subtract the product of the divisor and the quotient digit (2·15=30) and bring down the next digit of the original dividend. Now, you have a dividend of 147 and a divisor of 15. Repeat the process as above.
The decimal point location in the answer can be found a number of ways. The simpliest is to put it above the decimal point in the dividend. (When the divisor is not an integer, multiply or divide both divisor and dividend by the same power of 10 until it is.)