Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
A = l x w
225 = l * 13 3/4
225 ÷ 13 3/4 = l * 13 3/4÷ 13 3/4
16 4/11 = l
Length = 16 4/11 inches
Answer:
25500
Step-by-step explanation:
Answer:
Step-by-step explanation:
Think of this situation as a number line in which the team starts at 0 yd.
Gaining yards is the positive direction and losing yards is negative.
Start at 0 yd and go 5 yd to the right. You are at +5.
Then go 7 yd left. You end up at -2.
+5 – 7 = -2
6242 divided by 4 equals 1,560.5
