Sin45°=p/h
1/√2=x/4√2
x√2=4√2
x=4
The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
In polar form:
r = √(x² + y²) and cosФ = x / √(x² + y²)
Hence:
r(1 - 2cosФ) = 1
√(x² + y²) [1 - 2(x / √(x² + y²))] = 1
√(x² + y²) - 2x = 1
Take square of both sides:
x² + y² - 4x√(x² + y²) + 4x² = 1
The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
Find out more on equation at: brainly.com/question/2972832
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Answer:
no bro
Step-by-step explanation:
Answer:
X = 4, 3
Step-by-step explanation:
I don't know if that's what you were looking for
