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Elanso [62]
3 years ago
15

25% of what number is 13

Mathematics
2 answers:
Westkost [7]3 years ago
8 0

Answer: x = 52

Step-by-step explanation: Well <em>percent</em> means <em>over 100</em> so we know that 25% means 25/100. <em>Of</em> means <em>times</em>, <em>what number</em> means <em>x</em>, <em>is</em> means<em> equals</em>, and <em>12</em> means <em>12</em>. So we can translate this problem into an equation.

So we have the equation 25/100 · X = 13

Notice that 25/100 can be reduced to 1/4.

So rewriting our problem we have X/4 = 13.

To get rid of the fraction, we multiply both sides of the equation by 4 and we have <em>x = 52</em>.

This means that 25% of <em>52</em><em> </em>is 13.

Zielflug [23.3K]3 years ago
6 0

Answer: 52

Step-by-step explanation:

.25 · x =13

13/.25 = 52

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X + (x + 2) + ( x + 4) + (x + 6)
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4x + 12
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Multiply by 4 on both sides

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subtract 12 from both sides
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divide by 4 on each side
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3 years ago
Thirty-three college freshmen were randomly selected for an on-campus survey at their university. The participants' mean GPA was
Ivan

Answer: \pm0.1706

Step-by-step explanation:

Given : Sample size : n= 33

Critical value for significance level of \alpha:0.05 : z_{\alpha/2}= 1.96

Sample mean : \overline{x}=2.5

Standard deviation : \sigma= 0.5

We assume that this is a normal distribution.

Margin of error : E=\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. E=\pm (1.96)\dfrac{0.5}{\sqrt{33}}=\pm0.170596102837\approx\pm0.1706

Hence, the  margin of error is \pm0.1706

7 0
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Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi
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Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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381 meters because you divide 1250 by 3.281 and you get 381 meters

6 0
3 years ago
Read 2 more answers
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